The law of conservation of mass dictates that the total mass of reactants must be equal to the total mass of the products. Thus:
mass(MgO) = mass(Mg) + mass(O)
mass(MgO) = 24 + 16
mass(MgO) = 40 g
The third option is correct.
Answer:
mass water = 32.4 g
Explanation:
specific heat iron = 0.450 J/g°C
specific heat water = 4.18 J/g°C
32.8 x 0.450 ( 59.1 - 22.4) + mass water x 4.18 ( 59.1- 63.1)=0
541.7 - mass water x 16.7 = 0
mass water = 32.4 g
Answer:
PN₂ = 191.3 Kpa
Explanation:
Given data:
Total pressure of tire = 245.0 Kpa
Partial pressure of PO₂ = 51.3 Kpa
Partial pressure of PCO₂ = 0.10 Kpa
Partial pressure of others = 2.3 Kpa
Partial pressure of PN₂ = ?
Solution:
According to Dalton law of partial pressure,
The total pressure inside container is equal to the sum of partial pressures of individual gases present in container.
Mathematical expression:
P(total) = P₁ + P₂ + P₃+ ............+Pₙ
Now we will solve this problem by using this law.
P(total) = PO₂ + PCO₂ + P(others)+ PN₂
245 Kpa = 51.3 Kpa + 0.10 Kpa + 2.3 Kpa + PN₂
245 Kpa = 53.7 Kpa+ PN₂
PN₂ = 245 Kpa - 53.7 Kpa
PN₂ = 191.3 Kpa
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Answer:
449 mL
Explanation:
Using Ideal gas equation for same mole of gas as
Given ,
V₁ = 450 mL
V₂ = ?
P₁ = 101 kPa
P₂ = 104 kPa
T₁ = 17 ºC
T₂ = 25 ºC
The conversion of T( °C) to T(K) is shown below:
T(K) = T( °C) + 273.15
So,
T₁ = (17 + 273.15) K = 290.15 K
T₂ = (25 + 273.15) K = 298.15 K
Using above equation as:
Solving for V₂ , we get:
V₂ = 449 mL