Given what we know, we can confirm that despite not being able to provide a visual representation, if you were to create one, it would show the atoms in the substance moving with <u>more and more </u>energy over time until vaporization occurred.
<h3>What is vaporization?</h3>
- Vaporization is the changing of a liquid into a gas.
- This is known as a phase change.
- This happens when the atoms receive enough heat energy.
- The heat energy provides the atoms with kinetic energy and causes them to move faster over time.
- When the kinetic energy is enough to rupture the bonds that hold a liquid together, it becomes a gas.
Therefore, given that vaporization is when atoms within a substance gain so much kinetic energy that they are able to rupture the bonds that hold them relatively close together and change into a gas, we can confirm that a visual representation would have to be a diagram showing the increased movement of atoms over time.
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Answer: Br2 I2 N2 Cl2 H2 O2 F2 (7 elements)
Explanation:
How to remeber this: Hal-NOH or BrINCIHOF
halogens Nitrogen, Oxygen, and Hydrogen.
Answer:
5Fe⁺² + MnO₄⁻ + 8H⁺ => 5Fe⁺³ + Mn⁺² + 4H₂O
Explanation:
Fe⁺² + MnO₄⁻ + H⁺ => Mn⁺² + Fe⁺³ + H₂O
5(Fe⁺² => Fe⁺³ + 1e⁻) => 5Fe⁺² => 5Fe⁺³ + 5e⁻
<u>MnO₄⁻ + 5e⁻ => Mn⁺² => MnO₄⁻ + 8H⁺ + 5e⁻ => Mn⁺² + 4H₂O</u>
=> 5Fe⁺² + MnO₄⁻ + 8H⁺ => 5Fe⁺³ + Mn⁺² + 4H₂O
<u>Answer:</u>
It is the expression of Charles' Law.
<u>Explanation:</u>
The given expression V1T2 = V2T1 is the formula for the Charles' Law.
A special case of an ideal gas is named as the Charles' Law. This law applies to ideal gases only which are at constant pressure.
According to this law, the volume of a fixed mass of a gas is directly proportional to its temperature and is given by:
V1T2 = V2T1
Given: C3H8(g) + O2(g) ----> CO2 (g) + H2O (g)
Step : Put a 3 in front of CO2 (g) to balance C
=> C3H8(g) + O2(g) ----> 3CO2 + H2O to balance H
Step 2: Put a 4 in front of H2O
=> C3H8 (g) + O2(g) -----> 3CO2 (g) + 4H2O (g)
Step 3: Given that there are 3*2 + 4 = 10 O to the right side, put a 5 in front of O2 to balance O:
=> C3H8(g) + 5O2(g) -----> 3CO2(g) + 4H2O(g)
You can verify that the equation is balanced.
So, the answer is that the coefficient in front of O2 is 5.