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cestrela7 [59]
3 years ago
12

From this list, choose all of the ionic compounds. Check all that apply. View Available Hint(s) Check all that apply. POCl3 KOCH

2CH3 CH3OH SOCl2 CH3CH2CO2Na NaOH CH2
Chemistry
1 answer:
Alik [6]3 years ago
4 0

Answer: KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

Explanation:

It is known that ionic compounds are the compounds in which one atom transfer its valence electrons to another atom. Hence, during this transfer partial opposite charges tend to develop on the combing atoms due to which strong force of attraction exists between the atoms.

An ionic bond is always formed between a metal and a non-metal.

For example, KOCH_2CH_3, CH_3CH_2COONa, NaOH are all ionic compounds.

On the other hand, a compound formed due to sharing of electrons between the combining atoms is known as a covalent compound. Generally, a non-metal with same or different non-metal tends to form a covalent bond.

For example, POCl_{3}, SOCl_{2} etc are all covalent compounds.

Thus, we can conclude that KOCH_2CH_3, [tex]CH_3CH_2COONa, NaOH are all ionic compounds.

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What is Kb for N2H4 if the pH of a 0.158M solution of N2H5Cl is 4.5?
olasank [31]

Answer:

Kb= 1.58 * 10^{-6}

Explanation:

The correct question is

What is Kb for N2H4 if the pH of a 0.158M solution of N2H5Cl is 4.5?

Solution-

N2H4Cl hydrolyses on addition of water

The reaction equation is as follows -

N2H4+ + H2O ----> N2H4 + H3O+

Ka = \frac{K_w}{K_b} = \frac{10^{-14}}{K_b}

pH = 4.5

[H+] = 10^{-pH} = 10^{-4.5}

K_b=  \frac{10^{-14} }{K_b} =  \frac{Y_2}{0.158}  \\K_b= \frac{(10^{-4.5})^2}{0.158}\\=> Kb = 0.158 * 10-14 /(10-4.5)2

 Kb= 1.58 * 10^{-6}

3 0
2 years ago
A major chemical spill occurred five years ago at Baker’s Beach, the world’s sole nesting ground for Merrick sea turtles, and pr
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Answer:

A) Misinformation! Contradicts info given.

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5 0
3 years ago
P+O2 → P4O10
Assoli18 [71]
The answer is B, this is a synthesis reaction. A good way to identify a synthesis reaction is when there are multiple reactants, but only one product.
6 0
3 years ago
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What amount (moles) of compound is present in 1.00 g of each of the compounds in Exercise 54?
Anika [276]

Answer:

1. Caffeine, C₈H₁₀N₄O₂

Amount = 1.00/194 = 0.00515 moles

2. Ethanol, C₂H₅OH

Amount = 0.0217 moles

3. Dry Ice, CO₂

amount = 0.0227 moles

<em>Note: The question is incomplete. The compound are as follows:</em>

<em> 1. Caffeine, C₈H₁₀N₄O₂;</em>

<em>2. Ethanol, C₂H₅OH;</em>

<em>3. Dry Ice, CO₂</em>

Explanation:

Amount (moles) = mass in grams /molar mass in grams per mole

1. Caffeine, C₈H₁₀N₄O₂

molar mass of caffeine = 194 g/mol

Amount = 1.00 g/194 g/mol = 0.00515 moles

2. Ethanol, C₂H₅OH

molar mass of ethanol = 46 g/mol

Amount = 1.00 g/46 g/mol = 0.0217 moles

3. Dry Ice, CO₂

molar mass of dry ice = 44 g/mol

amount = 1.00 g/44 g/mol = 0.0227 moles

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Answer:

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Explanation:

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3 years ago
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