Question

Determine the ratio of electrostatic potential energies for CsF and Csl.

Answer 1

Answer:

The answer is "1.29".

Explanation:

Formula for electrostatic potential energy:

$\to V=\frac{K Q_1 \times Q_2}{r}$

where

$\to K = \text{electrostatic constant}\\\\\to Q= \text{Charge on Cation}$

The Charge on Cation is $C_{s}^{+}$ is cation in both $C_sI$ and $C_sF$ were same:

$\to V\ \alpha \ \frac{1}{r}$

$\to \frac{V(C_sF)}{V(C_sI)} = \frac{r(C_sI)}{r(C_sF)}$

                $= \frac{r(C_s^{+}) +r(I^{-})}{r(C_s^{+}) +r(F^{-})} \\\\=\frac{170+220}{170+133} \\\\=\frac{390}{303} \\\\ =1.2871 \\\\ =1.29$