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Artist 52 [7]
10 months ago
5

Sodium stearate (c17h35coona) is commonly used in soaps and detergents. a. what effect does a common ion have on solubility?

Chemistry
1 answer:
Triss [41]10 months ago
4 0

Sodium stearate is the sodium salt of stearic acid. This white solid is the most common soap. It is found in many types of solid deodorants, rubbers, latex paints, and inks.

It is also a component of some food additives and food flavorings.

Sodium stearate is a stabilizer and thickener that helps harden soaps and deodorants, allowing a wide variety of shapes and sizes and removing the need for unnecessary packaging and synthetic preservatives.

It also has opacifying properties that give the foam a creamy white appearance.

Sodium stearate is a vegetable-based soap material sourced from coconut and palm oils. It is often referred to as a sodium salt that comes from stearic acid, a fatty acid that occurs naturally.

Common Ion Effect on Solubility

Adding a common ion decreases solubility, as the reaction shifts toward the left to relieve the stress of the excess product.

Adding a common ion to a dissociation reaction causes the equilibrium to shift left, toward the reactants, causing precipitation.

To learn more about sodium stearate here

brainly.com/question/14928309

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A mole is __<br> - objects.<br> Answer here
ddd [48]

Answer:

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Explanation:

7 0
3 years ago
A hot lump of 39.9 g of iron at an initial temperature of 78.1 °C is placed in 50.0 mL H 2 O initially at 25.0 °C and allowed to
Drupady [299]

Answer : The final temperature of the mixture is 29.6^oC

Explanation :

In this problem we assumed that heat given by the hot body is equal to the heat taken by the cold body.

q_1=-q_2

m_1\times c_1\times (T_f-T_1)=-m_2\times c_2\times (T_f-T_2)

where,

c_1 = specific heat of iron = 0.499J/g^oC

c_2 = specific heat of water = 4.18J/g^oC

m_1 = mass of iron = 39.9 g

m_2 = mass of water  = Density\times Volume=1g/mL\times 50.0mL=50.0g

T_f = final temperature of mixture = ?

T_1 = initial temperature of iron = 78.1^oC

T_2 = initial temperature of water = 25.0^oC

Now put all the given values in the above formula, we get

(39.9g)\times (0.499J/g^oC)\times (T_f-78.1)^oC=-(50.0g)\times 4.18J/g^oC\times (T_f-25.0)^oC

T_f=29.6^oC

Therefore, the final temperature of the mixture is 29.6^oC

8 0
3 years ago
If 60. liters of hydrogen gas at 546 K is cooled to 273 K at constant pressure, the new volume of the gas would be
Korvikt [17]

Answer:30 L

Explanation:

Initial Volume

=

V

1

=

60

l

i

t

e

r

Initial Temperature

=

T

1

=

546

K

Final Temperature

=

T

2

=

273

K

Final Vloume

=

V

2

=

?

?

Sol:-

Since the pressure is constant and the question is asking about temperature and volume, i.e,

V

1

T

1

=

V

2

T

2

⇒

V

2

=

V

1

⋅

T

2

T

1

=

60

⋅

273

546

=

60

2

=

30

l

i

t

e

r

⇒

V

2

=

30

l

i

t

e

r

Hence the new volume of the gas is

30

l

i

t

e

r

6 0
3 years ago
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