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ra1l [238]
2 years ago
8

How many people can Liam buy lunch for

Mathematics
1 answer:
makvit [3.9K]2 years ago
7 0

Answer:

At most, Liam can only buy lunch for 6 people.

Step-by-step explanation:

It isn't going to be a decimal answer because there can't be half of a person

All you have to do is divide 50 by 8 and round down because you don't want to spend more than 50 dollars.

Writing it mathematically, it would be:

p \leq 6

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The tiles are identical, so you would need them to fit exactly.
if he uses 144 tiles to cover the floor, the area would be 72/144 = 0.5 square feet
this is just one example
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30 POINTS HELP ME-
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Answer:

Number line graph with closed circle on 30 and shading to the right

because you already have 30 dollars and they need at least 120 but if they get more then 120 they can still hold the science fair.

THIS ANSWER ISN'T MINE. I TOOK IT FROM AN ANSWER TO THE SAME QUESTION ANOTHER USER POSTED.

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2 years ago
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Hoping to attract more shoppers, a city builds a new public parking garage downtown. The city plans to pay for the structure thr
posledela

Answer:

MOE_{95} = 1.192\cdot MOE_{90}

Step-by-step explanation:

The margin of error is computed using the formula:

MOE=z_{\alpha/2}\cdot\frac{\sigma}{\sqrt{n}}

The critical of <em>z</em> for 95% confidence level and 90% confidence level are:

z_{0.05/2}=z_{0.025}=1.96\\\\z_{0.10/2}=z_{0.05}=1.645

*Use a <em>z</em>-table.

The sample size is n = 44.

Compare the MOE for 95% confidence level and 90% confidence level as follows:

\frac{MOE_{95}}{MOE_{90}}=\frac{1.96\times (15/\sqrt{44})}{1.645\times (15/\sqrt{44})}

\frac{MOE_{95}}{MOE_{90}}=\frac{1.96}{1.645}\\\\\frac{MOE_{95}}{MOE_{90}}=1.192\\\\MOE_{95} = 1.192\cdot MOE_{90}

6 0
3 years ago
Find the sum of the first six terms of the sequence for which a2=0.7 and a3=0.49.
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3 years ago
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There are 2 Senators from each of 50 states. We wish to make a 3-Senator committee in which no two members are from the same sta
Morgarella [4.7K]

Answer:

a) rCn = 1176

b) 2352

Step-by-step explanation:

a)Each committee should be formed with 3 members ( no two members could be of the same state) then

Let´s  fix a senator for any of the 50 states so in the new condition we need to combined 49 senators in groups of 2 then

rCn =  n! / (n - r )! *r!

rCn =  49!/ (49 - 2)!*2!

rCn =  49*48*47! / 47!*2!

rCn = 49*48 /2

rCn = 1176

So we can choose in 1176 different ways a senator for a given state

b) To answer this question we have to note, that, 1176 is the number of ways a committee can be formed with senators of different sate (taking just one senator for state ) if we have 2 senators we need to multiply that figure by 2.

1176*2 = 2352

6 0
3 years ago
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