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Georgia [21]
3 years ago
6

Being r // s, determine the value of x

Mathematics
1 answer:
Crank3 years ago
5 0
Im pretty sure x is 40 degrees
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Rina8888 [55]
Easy.

2x + 3x

2x + 3x

2x ( 1 + 3x / 2x )

2x ( 1 + 1.5 )

2x ( 3 )

6x

or

2x ( 3 )

or

3x ( 2 )

That's it.

Hope helps ...........

7 0
3 years ago
A circular piece of glass has a radius of 0.8 meters. The glass sells for $4.60 per m2.
Aleksandr-060686 [28]

A=pi r^2

then use your rate of $4.60/m^2 and multiply that by your area.

A = 3.14 (.8^2)

Cost = 2.01 m^2 $4.60/m^2 = $9.24

So your answer would be B

plz mark me as brainliest :)

6 0
4 years ago
Customers who purchase an aluminum-structured Audi A8 can order an engine in any of three sizes: 2.0L, 2.4L, and 2.8L. Of all Au
sergiy2304 [10]

Answer:

The probability that an Audi A8 car with 2.4L engine is selected given that the car failed emissions test taken within four years of purchase is 0.3589.

Step-by-step explanation:

Let's denote event as follows:

<em>A</em> = an Audi A8 car has a 2.0L engine.

<em>B</em> = an Audi A8 car has a 2.4L engine.

<em>C</em> = an Audi A8 car has a 2.8L engine.

<em>X</em> = an Audi A8 car failed emissions test taken within four years of purchase.

The information provided is:

P(A)=0.45\\P(B)=0.35\\P(C)=0.20\\P(X|A)=0.10\\P(X|B)=0.12\\P(X|C)=0.15

The probability that an Audi A8 car with 2.4L engine is selected given that the car failed emissions test taken within four years of purchase is:

P(B|X)=\frac{P(X|B)P(B)}{P(X)}

Compute the probability of an Audi A*8 car failed emissions test taken within four years of purchase as follows:

P(X)=P(X|A)P(A)+P(X|B)P(B)+P(X|C)P(C)\\=(0.45\times0.10)+(0.35\times0.12)+(0.20\times0.15)\\=0.117

Compute the value of P (B|X) as follows:

P(B|X)=\frac{P(X|B)P(B)}{P(X)}=\frac{0.35\times0.12}{0.117} =0.3589

Thus, the probability that an Audi A8 car with 2.4L engine is selected given that the car failed emissions test taken within four years of purchase is 0.3589.

4 0
4 years ago
Find the perimeter of the polygon with the given vertices x(-1,3) y(3,0) z(-1,-2)
Dvinal [7]

x(-1,3) y(3,0) z(-1,-2)

xy

m = (3 + 1)/(0 - 3) = 4/-3 = -4/3

y - 3 = -4/3(x + 1)

y - 3 = -4/3x - 4/3

xy: y = -4/3x + 5/3

yz

m = (0 + 2)/(3 + 1) = 2/4 = 1/2

y = 1/2(x - 3)

yz: y = 1/2x - 3/2

xz

m = (3 + 2)/(-1 + 1) = 5/0 = undefined

y - 3 = undefined(x + 1)

xz: x = -1

xy: y = -4x/3 + 5/3

yz: y = x/2 - 3/2

xz: x = -1

4 0
3 years ago
In a newspaper, it was reported that yearly robberies in Springfield were up 50% to 93 in 2013 from 2012. How many robberies wer
DiKsa [7]

Answer:

There were 62 deaths

Step-by-step explanation:

In this question, we are asked to calculate the number of robberies in 2012.

From the question we can identify that the number of robberies were up 50% to 93. What this means is that the number is simply 150% of the old number.

Now, let’s represent the number of deaths in 2012 by x

Mathematically;

150% of x = 93

150/100 * x = 93

150x = 93 * 100

150x = 9300

x = 9300/150

x= 62

This means there were 62 deaths in the year 2012

8 0
4 years ago
Read 2 more answers
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