<span><span>The answer is A.
</span><span>Chlorine is found in group7A of the periodic table. This means that when they are neutral, (electrons and protons are equal), they lack 1 electron to complete the octet or eight valence electrons to be stable. This will result in Chlorine having to gain an electron. Since it gained an electron, that means the electrons outnumber the protons by 1, which will result in a negative charge of -1. </span></span>
Kinetic energy<span> increases with the square of the velocity (KE=1/2*m*v^2). If the velocity is doubled, the KE quadruples. Therefore, the </span>stopping distance<span> should increase by a factor of four, assuming that the driver is </span>can<span> apply the brakes with sufficient precision to almost lock the brakes.</span>
False
It is experiencing net force
Answer:
#_foton2 = 2.96 10¹⁶ photon / s
Explanation:
We are going to solve this exercise in parts, first we will calculate how many photons are in the beam and then the amount that pass through the pinhole.
To find the energy of a photon, let's use the Planck relationship
E = h f
c = λ f
we substitute
E₀ = h c /λ
E₀ = 6.63 10⁻³⁴ 3 10⁸/337 10⁻⁹
E₀ = 5.90 10⁻¹⁹ J
Now we can use a direct ratio rule to find out the number of photons in the beam. If 1 photon has an energy E₀, how many photons are in an energy 5.00W
# _foton = 1 5/ E₀ = 1 5 / 5.90 10⁻¹⁹
#_foton = 8.5 10¹⁸ photons / s
This number of photons is uniformly distributed in the area of the circle with diameter 5.90mm = 5.90 10⁻³m
R= d/2= 2.95 10⁻³ m
r = d/2 = 0.55 10⁻³ m
let's find the beam area
A = π R²
A = π (2.95 10⁻³)²
A = 2.73 10⁻⁵ m²
the pinhole area
a = π r²
a = π (0.55 10⁻³)²
a = 9.50 10⁻⁷ m²
Let's use another direct ratio (rule of three) if there are 8.5 1018 photons / s in an area A how many photons pass through the area at
# _foton2 = 8.5 10¹⁸ a / A
# _fotn2 = 8.5 10¹⁸ 9.50 10⁻⁷ /2.73 10⁻⁵
#_foton2 = 2.96 10¹⁶ photon / s