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Sergio039 [100]
3 years ago
14

Which two lines are parallel? Which two lines are perpendicular?

Mathematics
1 answer:
lana66690 [7]3 years ago
7 0

Answer:

see explanation

Step-by-step explanation:

Parallel lines have equal slopes

The product of the slopes of perpendicular lines = - 1

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

All the equations given are in slope- intercept form

y = 2x + 1 → with m = 2

y = \frac{1}{2} x - 4 → with m = \frac{1}{2}

y = x + 1 → with m = 1

y = - \frac{1}{x} x - 3 → with m = - \frac{1}{2}

y = 10 + x → y = x + 10 → with m = 1

Thus

y = x + 1 and y = 10 + x are Parallel since both have m = 1

y = 2x + 1 and y = - \frac{1}{2} x - 3 are Perpendicular since 2 × - \frac{1}{2} = - 1

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Marcelo played a carnival games six times he spent three tokens to play each game and he won seven tokens each time write two di
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Answer:

24

Step-by-step explanation:

let W represent the number of wins

and let P represent the number of plays

let T represent profit from each play.

from the question, Marcelo played 3 times, this means 3P can represent the first equation

He won 7 times, 7W can represent the second equation

and T which is  profit is the difference between the number of tokens he won in each game and the number of tokens he spent to play each game.

Therefore, T = 7W - 3P

to get the total profit we will multiply T by the number of games played (in this case, 6)

this means that 6T = (7W - 3P) * 6

Since Marcelo spent and won tokens, the above expression of W and P can be expressed by a single variable. What this means is that, we can make 7W equal 7P or 3P equal 3W since we are dealing in the same item (tokens won and played)

profit per game (T) = 7P - 3P = 4P

total profit (for 6 games) = 4P * 6 =24

Second expression

we can also look at it from this angle;

-3 tokens+7 tokens = profit per game

profit per game for Marcelo = 4 tokens

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total profit for Marcelo =6*4 = 24

8 0
3 years ago
WILL MARK BRINLIEST. Can someone help me wit den two questions?
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Step-by-step explanation:

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2 years ago
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In a multiple choice quiz there are 5 questions and 4 choices for each question (a, b, c, d). Robin has not studied for the quiz
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Answer:

a) There is a 18.75% probability that the first question that she gets right is the second question.

b) There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

c) There is a 10.35% probability that she gets the majority of the questions right.

Step-by-step explanation:

Each question can have two outcomes. Either it is right, or it is wrong. So, for b) and c), we use the binomial probability distribution to solve this problem.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

In which C_{n,x} is the number of different combinatios of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And \pi is the probability of X happening.

In this problem we have that:

Each question has 4 choices. So for each question, Robin has a \frac{1}{4} = 0.25 probability of getting ir right. So \pi = 0.25. There are five questions, so n = 5.

(a) What is the probability that the first question she gets right is the second question?

There is a 75% probability of getting the first question wrong and there is a 25% probability of getting the second question right. These probabilities are independent.

So

P = 0.75(0.25) = 0.1875

There is a 18.75% probability that the first question that she gets right is the second question.

(b) What is the probability that she gets exactly 1 or exactly 2 questions right?

This is: P = P(X = 1) + P(X = 2)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 1) = C_{5,1}.(0.25)^{1}.(0.75)^{4} = 0.3955

P(X = 2) = C_{5,2}.(0.25)^{2}.(0.75)^{3} = 0.2637

P = P(X = 1) + P(X = 2) = 0.3955 + 0.2637 = 0.6592

There is a 65.92% probability that she gets exactly 1 or exactly 2 questions right.

(c) What is the probability that she gets the majority of the questions right?

That is the probability that she gets 3, 4 or 5 questions right.

P = P(X = 3) + P(X = 4) + P(X = 5)

P(X = x) = C_{n,x}.\pi^{x}.(1-\pi)^{n-x}

P(X = 3) = C_{5,3}.(0.25)^{3}.(0.75)^{2} = 0.0879

P(X = 4) = C_{5,4}.(0.25)^{4}.(0.75)^{1} = 0.0146

P(X = 5) = C_{5,5}.(0.25)^{5}.(0.75)^{0} = 0.001

P = P(X = 3) + P(X = 4) + P(X = 5) = 0.0879 + 0.0146 + 0.001 = 0.1035

There is a 10.35% probability that she gets the majority of the questions right.

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inna [77]

Answer:

(x+2)^2/16 - (y-1)^2/9 = 1

Step-by-step explanation:

I just did this problem for edgen 2020.

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2 years ago
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