Which statement about determining the quotient 12÷14 is true?

The janitor at a school discovered a leak in a pipe. The janitor found that it was leaking at a rate of 11 fl oz per hour. How f

netineya [11]

Here's what you need to know in order to answer this:

   1 gallon = 128 fl oz
and
   1 day = 24 hours.

Use those facts to invent fractions equal to ' 1 '.
Then use those to change the units of the "11 fl oz per hour".
You can multiply them ... since their value is ' 1 ', they won't
change the value of the "11 fl oz per hour", only the units.

(11 fl oz/hr) x (24 hr/da) x (1 gal / 128 fl oz)

   = (11 x 24 x 1 / 128) (fl-oz - hr - gal) / (hr - da - fl-oz)

   =     2.0625    gal/da

6 0

2 years ago

A meteorologist measures the angle of elevation of a weather balloon is 41 degrees. A radio signal from the balloon indicates th

I am Lyosha [343]

You can draw a diagram of the situation, representing it by a right triuangle.

In the right triangle the hypotenuse is the distance indicated by the radio signal, 1503 m, and the angle is 41°.

The opposed leg to 41° is the height of the ballon.

Then you can use the sine trigonometric function.

sine (41°) = opposed leg / hypotenuse = x / 1503 m => x = 1503m * sine(41°)

=> x = 986m.

Answer: 986m

4 0

2 years ago

You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp

Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2$

after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

8 0

2 years ago

i need help. Semir, Sarah, and SungSo decided to raise money for a local homeless shelter by working in a local deli. The deli a

IgorLugansk [536]

According to the question,
Let,
"n" represent the number of miles semir walked.
"y" represent the number of miles sarah walked.
Now, according to the question,

y = 2n - 5 ........................this is your equation
Also,
the question states, each of them collect $18 in pledges for every miles walked.

Given,
Sarah collected $450
Now,

Using unitary method,

Sarah collects $18 for 1 mile
Sarah collects $1 for (1 / $18) mile
Sarah collects $450 for (1 / 18) * 450 mile
= 25 miles
So, Sarah walks 25 miles.
Now,
Taking equation,
y = 2n - 5
Since, y is the no. of miles sarah walked, we can write 25 in place of "y" So,
(25) = 2n - 5
25 + 5 = 2n
30 = 2n
30 / 2 = n
15 = n

Since, "n" is the no. of miles that semir walked, Semir walked 15 miles.

7 0

3 years ago

A nick on the edge of a CD rotates to (−6, 5) during one song when represented graphically.

Allisa [31]

By definition, the sine of an angle is given by:
$sin \alpha = \frac{C.O}{h}$
Where,
C.O: opposite leg
h: hypotenuse
The hypotenuse is given by:
$h = \sqrt{(-6)^2+(5)^2}$
$h = \sqrt{(61}$
So, replacing values we have:
$sin \alpha = \frac{5}{\sqrt{61}}$
Rewriting we have:
$sin \alpha = \frac{5\sqrt{61}}{61}$
Answer:
the sine value of this function is:
A)5 times square root 61 over 61

6 0

3 years ago

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