Which statement about determining the quotient 12÷14 is true?

Read the excerpt from act 1 of The Monsters Are Due on Maple Street.

Vika [28.1K]

Answer:

it is D. the murmurs of a group

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

3 years ago

Aya = a1 + (n - 1)d

Alenkasestr [34]

Answer:

The 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

Step-by-step explanation:

Given

a₁ = -33

d = 4

An arithmetic sequence has a constant difference 'd' and is defined by

$a_n=a_1+\left(n-1\right)d$

substituting a₁ = -33 and d = 4 in the nth term of the sequence

$a_n=-33+\left(n-1\right)4$

$\:a_n=-33+4n-4$

$a_n=4n-37$

Thus, the nth term of the sequence is:

$a_n=4n-37$

now substituting n = 26 in the nth term to determine the 26th term of the sequence

$a_n=4n-37$

$a_{26}=4\left(26\right)-37$

$a_{26}=104-37$

$a_{26}=67$

Therefore, the 26th term of an arithmetic sequence is:

$a_{26}=67$

Hence, option A is true.

7 0

3 years ago

A falcon flew 70 miles in 3 hours. What was the speed of the falcon?

Nadusha1986 [10]

Using the given formula speed = distance over time:

Speed = 70 miles / 3 hours

Speed = 23.33 miles per hour

Convert miles per hour to meters per hour:

1 mile = 1609 meters:

23.33 miles x 1690 meters = 37,543.33 meters per hour.

Now convert meters per hour to meters per second:

1 hour = 3600 seconds:

37,543.33 / 3600 = 10.4 meters per second.

4 0

3 years ago

The area of a trapezium is 35cm2.find its altitude if the bases is 6cm and 8cm

r-ruslan [8.4K]

Answer: altitude: 5 cm

Explanation:

$\sf \dfrac{1}{2} ( a + b) h = Area \ of \ trapezium$

[ <u>a and b are bases, h is the altitude</u> ]

Here given:

Area = 35

a = 6

b = 8

h = ?

Solve for altitude:

$\sf \rightarrow \sf \dfrac{1}{2} ( 6 + 8) h = 35 \ \ \ \Rightarrow \ \ \ \dfrac{1}{2} ( 14) h = 35 \ \ \ \ \Rightarrow \ \ \ \ 7 h = 35 \ \ \ \ \Rightarrow \ \ h = \dfrac{35}{7} \ = \ 5$

7 0

2 years ago