Answer:
First confirm the reaction is balanced:
C3H8 + 5O2 --> 3CO2 + 4H20 (3 cabon - check; 8 hydrogen - check; 10 oxygen - check).
a) In the equation there is a 5:1 ratio between propane and oxygen. We also know that number of mole is proportional to pressure and volume. Since pressure is constant (STP) then the volume of O2 is 7.2 * 5 = 36 litres.
b) For a near ideal gas that PV = nRT (combined gas law). So for 7.2 litres propane we find n(propane) = 101.3 * 7.2/8.314*298 ~ 0.29 mole (using metric units throughout for simplicity).
There is a 1:3 ratio between propane and CO2. Therefore 3 * 0.29 = 0.87 mole of CO2 is produced.
MW(CO2) ~ 44 g/mol. Therefore m(CO2) = 44 * 0.87 ~ 38.3 g
c) We know we need more oxygen than propane (due to the 1:5 ratio) so oxygen is the limiting reagent. Again Volume is proportional to number of mole and we see there is a 5:4 ratio between oxygen and water. Therefore the volume of water vapour produced will be (4/5) * 15 = 12 litres.
The other questions use the same technique and will give you some much needed practice.
Explanation:
A dilute acid solution is prepared by adding the concentrated acid to water. If you do the reverse, i.e. add water to the acid it is possible that a small amount water could react with acid and boil and explode thus splashing the acid onto you or someone else near the activity.
It is a period.....
this ok??
Hello!
The balanced chemical equation for the rusting of iron is the following:
4 Fe + 3 O₂ → 2Fe₂O₃
The coefficients to balance the equation are 4,3,2. The fundament of this balance is the Law of Conservation of Mass. This Law states that matter is neither created nor destroyed in a chemical reaction, and in a chemical equation, the moles of each atom is conserved in both sides of the arrow. That means that if 4 Fe atoms are on the left side, 4 Fe atoms should be on the right side.
A suggestion for balancing equations is to start with metal atoms, continuing with non-metals, then hydrogen and lastly oxygen.
Have a nice day!
<u>Answer:</u> The additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X
<u>Explanation:</u>
To calculate the mole percent of a substance, we use the equation:
Mass percent means that the mass of a substance is present in 100 grams of mixture
To calculate the number of moles, we use the equation:
We require the molar masses of Z and X to calculate the mole percent of Z and X respectively
Hence, the additional information that is helpful in calculating the mole percent of XCl(s) and ZCl(s) is the molar masses of Z and X
