Answer:
2.94
Explanation:
There is some info missing. I think this is the original question.
<em>A solution is prepared at 25 °C that is initially 0.38 M in chloroacetic acid (HCH₂ClCO₂), a weak acid with Ka= 1.3 x 10⁻³, and 0.44 M in sodium chloroacetate (NaCH₂CICO₂). Calculate the pH of the solution. Round your answer to 2 decimal places.</em>
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We have a buffer system formed by a weak acid (HCH₂ClCO₂) and its conjugate base (CH₂CICO₂⁻ coming from NaCH₂CICO₂). We can calculate the pH using the Henderson-Hasselbalch equation.
pH = pKa + log [CH₂CICO₂⁻]/[HCH₂ClCO₂]
pH = -log 1.3 x 10⁻³ + log (0.44 M/0.38 M)
pH = 2.94
Answer:
Element Symbol # of Atoms
Iron Fe 2
Oxygen O 12
Sulfur S 3
The 410 mm wavelength corresponds to the n=6 to n=2 transition, the 434
mm wavelength corresponds to the n=5 to n=2 transition.
Planck's equation: E=hc/wavelength
n=6 to n=2 corresponds to a higher energy transition and hence shorter wavelength, 410nm.
