Answer:
Aerobic exercise became part of this movement in the 1970s.
Cubic centimeters for the volume of a solid.
Liters for volume of a liquid.
As the speed of airplane is change due to jet stream
So the net speed is given as
![v_{net} = v_{plane} + v_{stream}](https://tex.z-dn.net/?f=v_%7Bnet%7D%20%3D%20v_%7Bplane%7D%20%2B%20v_%7Bstream%7D)
now we can rearrange it as
![v_{plane} = v_{net} - v_{stream}](https://tex.z-dn.net/?f=v_%7Bplane%7D%20%3D%20v_%7Bnet%7D%20-%20v_%7Bstream%7D)
now by the formula of vector difference we have
![v_{plane} = \sqrt{v_{net}^2 + v_{stream}^2 - 2v_{net}v_{stream}cos\theta}](https://tex.z-dn.net/?f=v_%7Bplane%7D%20%3D%20%5Csqrt%7Bv_%7Bnet%7D%5E2%20%2B%20v_%7Bstream%7D%5E2%20-%202v_%7Bnet%7Dv_%7Bstream%7Dcos%5Ctheta%7D)
now plug in all values
![v_{plane} = \sqrt{365^2 + 136.73^2 - 2* 365* 136.73*cos22}[tex]v_{plane} = 243.7 km/hr](https://tex.z-dn.net/?f=v_%7Bplane%7D%20%3D%20%5Csqrt%7B365%5E2%20%2B%20136.73%5E2%20-%202%2A%20365%2A%20136.73%2Acos22%7D%3C%2Fp%3E%3Cp%3E%5Btex%5Dv_%7Bplane%7D%20%3D%20243.7%20km%2Fhr)
so above is the speed of the plane
Solution:
54 / 9 = 6 boxes.