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sveticcg [70]
4 years ago
10

A conductor carries a current that is decreasing exponentially with time. The current is modeled as ????=????0????−????/???? , w

here ????0=3.00A is the current at time ????=0.00s and ????=0.50s is the time constant. How much charge flows through the conductor between ????=0.00s and ????=3???? ?
Physics
1 answer:
Vlad1618 [11]4 years ago
3 0

Answer:

Q=1.42 C

Explanation:

Given that

I=I_oe^{\dfrac{-t}{\tau}}

When t= 0 ,Io = 3 A

τ = Time constant = 0.5 s

I=3e^{-\dfrac{t}{\tau}}

We know that

I=\dfrac{dQ}{dt}

Q=Charge ,I =Current

Q = ∫I.dt

Given that

t= 0 to t= 3τ= 1.5 s

The charge Q

Q=\int_{0}^{1.5}3e^{-\dfrac{t}{0.5}}dt

Q=1.42 C

Therefore charge flow conductor will be 1.42 C.

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4 years ago
____________ are used to calculate the distance a continent has moved in a year. a. Space satellites c. Laser beams b. Mirrors d
Law Incorporation [45]
<span> Space satellites, laser beams, mirrors</span> are used to calculate the distance a continent has moved in a year.

Therefore, your correct answer would be "all of the above".
4 0
3 years ago
A student is pushing a box across the room. To push the box three times farther, the student needs to do how much work?
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Answer:

Removing some of the books reduced the mass of the box, and less force was needed to push it across the floor.

8 0
3 years ago
A bike travels at 7.5 m/s along a straight road, whereas a car travels at 10.0 m/s along the same road and in the same direction
Ilya [14]

Answer:

t = 8.3 s

Explanation:

As we know that

velocity of bike = 7.5 m/s

velocity of car is 10 m/s

deceleration of car is 0.75 m/s^2

part a)

velocity of bike with respect to car is given as

v_r = 7.5 - 10 = -2.5 m/s

acceleration of bike with respect to car is given as

a_r = 0 - (-0.75) = 0.75 m/s^2

now the distance of the bike with respect to car is given as

d = v_i t + \frac{1}{2}at^2

5 = (-2.5) t + \frac{1}{2}(0.75)t^2

t = 8.3 s

Part b)

3 0
3 years ago
If izzy mass is 0.3kg he applide 657.9n force what will be the accelration​
Sholpan [36]

Answer:

The acceleration of the body, a = 2193 m/s²

Explanation:

Given,

The mass of the body, m = 0.3 kg

The force acting on the body, F = 657.9 N

The force acting on an object is proportional to the product of mass and acceleration of the body.

                         F = m x a

Therefore, the acceleration of the body is

                           a = F / m

                              = 657.9 N / 0.3 kg

                              = 2193 m/s²

Hence, the acceleration of the body, a = 2193 m/s²

4 0
4 years ago
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