A solid sphere is placed on a frictionless floor in a very long corridor and is given a quick push so that it begins to slide, w
ithout rotating, along the corridor. How would the angular speed of the sphere be changing if the floor were not frictionless?
A.) It would remain zero because the net torque is still zero.
B.) It would remain zero because the angular momentum is conserved.
C.) It would be increasing until the slipping between the sphere and the floor stops.
D.) It would be increasing until the linear and the angular speeds become equal.
E.) It would be increasing until the translational motion stops.
A.) It would remain zero because the net torque is still zero.
B.) It would remain zero because the angular momentum is conserved.
C.) It would be increasing until the slipping between the sphere and the floor stops.
D.) It would be increasing until the linear and the angular speeds become equal.
E.) It would be increasing until the translational motion stops.
1 answer:
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Answer:
that best describes the process is C
Explanation:
This problem is a calorimeter process where the heat given off by one body is equal to the heat absorbed by the other.
Heat absorbed by the smallest container
Q_c = m ce (-T₀)
Heat released by the largest container is
Q_a = M ce (T_{i}-T_{f})
how
Q_c = Q_a
m (T_{f}-T₀) = M (T_{i} - T_{f})
Therefore, we see that the smaller container has less thermal energy and when placed in contact with the larger one, it absorbs part of the heat from it until the thermal energy of the two containers is the same.
Of the final statements, the one that best describes the process is C
since it talks about the thermal energy and the heat that is transferred in the process
(a) The capacitance of the capacitor is:
and the voltage applied across its plates is
The relationship between the charge Q on each plate of the capacitor, the capacitance and the voltage is:
and re-arranging it we find the charge stored in the capacitor:
(b) The electrical potential energy stored in a capacitor is given by
where C is the capacitance and V is the voltage. The new voltage is
so the energy stored in the capacitor is
and the voltage applied across its plates is
The relationship between the charge Q on each plate of the capacitor, the capacitance and the voltage is:
and re-arranging it we find the charge stored in the capacitor:
(b) The electrical potential energy stored in a capacitor is given by
where C is the capacitance and V is the voltage. The new voltage is
so the energy stored in the capacitor is