Answer:
6.132
Step-by-step explanation:
please mark me the brainiest
means to say that for any given 
, we can find 
such that anytime 
(i.e. the whenever 
is "close enough" to 5), we can guarantee that 
(i.e. the value of 
is "close enough" to the limit value).
What we want to end up with is
Dividing both sides by 3 gives
which suggests 
is a sufficient threshold.
The proof itself is essentially the reverse of this analysis: Let be given. Then if
and so the limit is 7. QED
Well, first start by making it look simpler by separating it by commas.
So.
309, 099, 990.
That number is in the hundred millions, soooo.
Three hundred million, ninety nine thousand, nine hundred and ninety.
I need a better picture of the shape
