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Troyanec [42]
3 years ago
13

Need help on this question 36

Mathematics
1 answer:
frosja888 [35]3 years ago
5 0
For the bottom, to find the top side of the triangle, 10-4, as seen from the top and bottom sides of the rectangle. So 6.

To find  the left side of triangle, subtract 12 from 8. 12 from the left and 8 from the rectangle. This gives you 4.

Now that we have 6 and 4, we can find the area:

A= ab/2

A= (6*4)/2

A=24/2

A=12 mm^2
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Can someone solve this! Need it done soon
Airida [17]

Answer:

117.5 ft²

Step-by-step explanation:

To find the area of the shaded area, we can find the area of the square, then subtract the areas of the two semicircles.

First, we will find the area of the given square, by using the formula lw, multiplying the length and width. The dimensions of this square are 14×14.

14 · 14 = 196

The area of the square is 196 ft².

We can now find the area of the two congruent half-circles. Since they are identical, we can simply find the area of one circle if it was whole. To find the area of a circle, we'll use the formula A=\pi r^2. With some simple deduction, we can see that the diameter of the circle is 10 ft, so the radius would be 5 ft long. Plug our values into the formula.

A = \pi5²

We will use 3.14 for \pi.

A = 78.5

The area of both the semicircles is 78.5 ft².

Now, we can subtract.

196 - 78.5 = 117.5

The area of the figure is 117.5 ft².

Good luck ^^

7 0
3 years ago
Math help please (80 points)
Inga [223]

Answer:

1. x^4 -x^3 -4x^2 -3

a1 = -7.4

an = an-1 -13.8  (choice 1)

Step-by-step explanation:

f(x) = x^4 -x^2 +9

g(x) = x^3 +3x^2 +12

We are subtracting

f(x) -g(x) =x^4 -x^2 +9 - ( x^3 +3x^2 +12)

Distribute the minus sign

x^4 -x^2 +9 -  x^3 -3x^2 -12

I like to line them up vertically

x^4      -x^2 +9

-  x^3 -3x^2 -12

-------------------------

x^4 -x^3 -4x^2 -3


2.  a1 = -7.4

To find the common difference, take term 2 and subtract term 1

-21.2 - (-7.4)

-21.2 + 7.4

-13.8

an = an-1 -13.8

5 0
3 years ago
Read 2 more answers
........................​
shtirl [24]

Answer:

Step-by-step explanation:

Figure (1)

x° = 107° [Vertically opposite angles]

Since, vertical angles are equal in measure.

Figure (2)

x + 71° = 90° [Given, complementary angles]

x = 90° - 71°

x = 19°

Figure (3)

x + 21° = 180° [Given as supplementary angles]

x = 180° - 21°

x = 159°

Figure (4)

x = 129° [Vertical angles]

Figure (5)

x° = 90° [Given]

z° + 34° = 90°

z° = 90° - 34°

z° = 56°

Since, x° + y° + z° = 180° [Linear angles]

90° + y° + 56° = 180°

y° + 146° = 180°

y° = 180° - 146°

y° = 34°

7 0
3 years ago
Help (20 points, due tmr!! )<br><br> *pic below* :)
sveta [45]
Angles:
2 acute angles and 2 obtuse angles

Sides:
2 pairs pf parallel sides
7 0
3 years ago
d^2y/dx^2=sqrt(1+(dy/dx)^2 state the order of the given ordinary differential equation. Determine whether the equation is linear
Georgia [21]
This is a second-order ODE since the highest order derivative is 2 (from \dfrac{\mathrm d^2y}{\mathrm dx^2}).

It's not linear because it doesn't take the form

F\left(\dfrac{\mathrm d^2y}{\mathrm dx^2},\dfrac{\mathrm dy}{\mathrm dx},y,x\right)=0\iff f_2(x)\dfrac{\mathrm d^2y}{\mathrm dx^2}+f_1(x)\dfrac{\mathrm dy}{\mathrm dx}+f_0(x)y+g(x)=0

and it's not possible to rewrite it as such.
5 0
3 years ago
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