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2 years ago

[EXTENDED RESPONSE SHOW ALL WORK.]

Mathematics

1 answer:

Lapatulllka [165]2 years ago

4 0

A.) the greatest amount of boxes would probably be 8
B.) the amount of cars would be 5 and the airplanes would be 3

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Four students are determining the probability of flipping a coin and it landing head's up. Each flips a coin the number of times

Oxana [17]

Answer:

Collin

Step-by-step explanation:

He did the most attempts.

The probability of flipping a coin is 1/2

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3 years ago

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Y=arccos(1/x)<br><br> Please help me do them all! I don’t know derivatives :(

Stells [14]

Answer:

$f(x) = {sec}^{ - 1} x \\ let \: y = {sec}^{ - 1} x \rightarrow \: x = sec \: y\\ \frac{dx}{dx} = \frac{d(sec \: y)}{dx} \\ 1 = \frac{d(sec \: y)}{dx} \times \frac{dy}{dy} \\ 1 = \frac{d(sec \: y)}{dy} \times \frac{dy}{dx} \\1 = tan \: y.sec \: y. \frac{dy}{dx} \\ \frac{dy}{dx} = \frac{1}{tan \: y.sec \: y} \\ \frac{dy}{dx} = \frac{1}{ \sqrt{( {sec}^{2} \: y - 1}) .sec \: y} \\ \frac{dy}{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} } \\ \frac{d( {sec}^{ - 1}5x) }{dx} = \frac{1}{ |5x | \sqrt{25 {x }^{2} - 1} }\\\\y=arccos(\frac{1}{x})\Rightarrow cosy=\frac{1}{x}\\x=secy\Rightarrow y=arcsecx\\\therefore \frac{d( {sec}^{ - 1}x) }{dx} = \frac{1}{ |x | \sqrt{ {x }^{2} - 1} }$

4 0

2 years ago

A cake has circumference of 25 1/7inches. What is the area of the cake? Use 22/7 to approximate π. Round to the nearest hundredt

bixtya [17]

We know that
area of the circle=pi*r²

circumference==2*pi*r----------> r=circumference/(2*pi)
circumference=25 1/7 in----> (25*7+1)/7----> 176/7 in
r=(176/7)/(2*22/7)----> r=176/44----> r=4 in

area of the circle is equal to the area of the cake
area=pi*r²---> (22/7)*4²-----> area=50.29 in²

the answer is
50.29 in²

5 0

2 years ago

Use the formula to find the length of the base next to the goal given that the height of the trapezoid is 11ft and the base fart

Liono4ka [1.6K]

Answer:

b1 = 22 ft

the length of the base next to the goal is 22 ft

Step-by-step explanation:

From the given formula;

Area A = 1/2×(b1 + b2)h ........1

Given;

Area A = 275ft^2

base b2 = 28 ft

base b1 = ?

height h = 11 ft

From equation 1;

Making b1 rhe subject of formula;

A = 1/2×(b1 + b2)h

Multiply through by 2;

2A = (b1+b2)h

b1+b2 = 2A/h

b1 = 2A/h - b2 ...... 2

Substituting the given values into equation 2;

b1 = 2(275)/11 - 28

b1 = 50 - 28

b1 = 22 ft

the length of the base next to the goal is 22 ft

5 0

2 years ago

The quadrilateral ABCD has an area of 58 in2 and diagonal AC = 14.5 in. Find the length of diagonal BD if AC ⊥ BD.

diamong [38]

So the quadrilateral is a rhombus. RSM Is hard and etc...
Anyways if the area = $58^{2}$ and we know that one diagonal is 14.5 inches and we know that the area of a rhombus is
$\frac{D^{1} * D^{2}}{2} =$
then we can do inverse operation and do
$\frac{54}{14.5} = 4$
4 * 2 because of the inverse operation has to be done to get the right answer and then you get the length of diagonal 2 is 8 in

4 0

3 years ago