Answer/Step-by-step explanation:
✔️Find EC using Cosine Rule:
EC² = DC² + DE² - 2*DC*DE*cos(D)
EC² = 27² + 14² - 2*27*14*cos(32)
EC² = 925 - 756*cos(32)
EC² = 283.875639
EC = √283.875639
EC = 16.85 cm
✔️Find the area of ∆DCE:
Area = ½*14*27*sin(32)
Area of ∆DCE = 100.15 cm²
✔️Since ∆DCE and ∆ABE are congruent, therefore,
Area of ∆ABE = 100.15 cm²
✔️Find the area of the sector:
Area of sector = 105/360*π*16.85²
Area = 260.16 cm² (nearest tenth)
✔️Therefore,
Area of the logo = 100.15 + 100.15 + 260.16 = 460.46 ≈ 460 cm² (to 2 S.F)
Step-by-step explanation:
123456 less then 7
unlimited greater then 7
Answer:
c because it will be half of it meaning you have to multiply rhem
Answer:
Step-by-step explanation:
(a) You use the fact that the lengths RS and ST total the length RT.
RS +ST = RT
(6y+3) +(3y+5) = 80 . . . . . substitute the given values
9y +8 = 80 . . . . . . . . . . . . .simplify
9y = 72 . . . . . . . . . . . . . . . .subtract 8
72/9 = y = 8 . . . . . . . . . . . .divide by the coefficient of y
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(b) Now, the value of y can be substituted into the expressions for RS and ST to find their lengths.
RS = 6y +3 = 6·8 +3
RS = 51
ST = 3y +5 = 3·8 +5
ST = 29
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<em>Check</em>
RS +ST = 51 +29 = 80 = RT . . . . the numbers check OK
A 270° counterclockwise rotation leads to this transformation:
(x,y) → (y, - x)
So, we have
original point new point
J (-6,2) → J' (2,6)
K (-4,6) → K' (6,4)
L (-3,3) → L' (3,3)
M (-5,-1) → M' (-1,5)
So, you have the points J', K', L', and M' that define the new parallelogram.
Answer: The coordinates of the endpoints of the side congruent to side KL are the coordinates of K' and L' which are (6,4) and (3,3).
