Use pythagoras
d = √(Δx² + Δy²)
d = √(12-2)² + (9-4)²
d = √(10² + 5²)
d = √(100 + 25)
d = √125
d = 5√5
d = 5 × 2.236
d = 11.18
The nearest tenth is 11.2, so the distance is near to 11.2
Answer:
D
Step-by-step explanation:
Answer:
c
Step-by-step explanation:
Answer:
15cm
Step-by-step explanation:
scale factor =image diatace/object distance
0.75=x/20
0.75×20=x
15=x
: .x=15cm
The line can be written in the form y=mx+b. Plugging -2 in for m , 1 in for x, and -3 in for y, we get -3=-2*1+b=-2+b. Adding 2 to both sides, we get b=-1 and our equation turns into y=-2x-1 since y and x stay variables. Plugging it into a graphing calculator, we get in (0,b) that b = -1
