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3 years ago

Ten moles of hydrogen are allowed to react with 6 moles of oxygen. How much water will be

Chemistry

1 answer:

Anastaziya [24]3 years ago

3 0

Answer:

10 moles of water are produced,

Explanation:

Given data:

Moles of H = 10 mol

Moles of O = 6 mol

Water obtained = ?

Solution:

Balance chemical equation:

2H₂ + O₂ → 2H₂O

Now we will compare the moles of H₂ and O₂ with water from balance chemical equation.

H₂ : H₂O

2 : 2

10 : 10

O₂ : H₂O

1 : 2

6 : 2×6 = 12

Number of moles of water produced by hydrogen are less so hydrogen will be limiting reactant and it will limit the yield of water thus, 10 moles of water are produced.

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1 year ago

consider one glucose unit in glycogen. what is the overall or net reaction for the conversion of this unit into 2 pyruvate, star

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This cycle is known as Glycolysis

Glycolysis is the 10 step process, which occurs in cytoplasm of cell and is conversion of glucose to pyruvate.

There are several steps and enzymes that is required in glycolysis pathway.

STEP 1: PHOSPHORYLATION

This is irreversible reaction.

Here glucose is phosphorylated to glucose 6 phosphate with the help of enzyme hexokinase and 1 ATP is utilized.

STEP 2 : ISOMERISATION

The isomerization of Glucose-6-phosphate to Fructose-6-phosphate, done with the help of enzyme phosphoglucoisomerase.

STEP 3 : SECOND PHOSPHORYLATION

Fructose-1,6-bisphosphate is phosphorylated to Fructose 1,6 bisphosphate which is catalyzed by phosphofructokinase and cost another ATP.

STEP 4: BREAKDOWN

The fructose-1,6 bisphosphate is breaken down too produce two 3carbon molecules - Glyceraldehyde-3-phosphate, or GADP, and a molecule of Dihydroxyacetone phosphate or DHAP.

The reaction is catalyzed by aldolase.

STEP 5 : CONVERSION OF DHAP INTO GADP

DHAP is oxidized to form GADP.

The reaction is catalyzed by triose phosphate isomerase enzyme.

STEP 6: OXIDATION

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STEP 7: DEPHOSPHORYLATION

First substrate level phosphorylation ( addition of phosphate to ADP to give ATP )

1,3 bisphosphoglycerate with the help of Phosphoglycerate kinase become 3-phosphoglycerate and will produce 1 ATP.

STEP 8: PHOSPHATE TRANSFER

The phosphate ester linkage in 3 phosphoglycerate is moved from 3 C to 2 , because of low free energy to form 2 phosphoglycerate with the help of phosphoglycerate mutase .

STEP 9: DEHYDRATION

2 phopshoglycerate is dehydrated by enolase to form Phosphoenolpyruvate ( PEP)

This is reversible reaction.

STEP 10: SECOND DEPHOSPHORYLATION

2 substrate level phosphorylation which gives out ATP.

Non - oxidative phosphorylation.

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To know more about glycolysis -

brainly.com/question/26990754

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