441 g CaCO₃ would have to be decomposed to produce 247 g of CaO
<h3>Further explanation</h3>
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Decomposition of CaCO₃
CaCO₃ ⇒ CaO + CO₂
mass CaO = 247 g
mol of CaO(MW=56 g/mol) :
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From equation, mol ratio CaCO₃ : CaO = 1 : 1, so mol CaO :

mass CaCO₃(MW=100 g/mol) :

It's called simple diffusion, the small molecules without charges such as oxygen and carbon dioxide can flow through a plasma membrane without assistance and without expending energy. Other substances such as proteins, glucose and charged particles called ions cannot pass through the selectively permeable membrane.
Answer:
9.55 grams of SiO2
Explanation:
If the mass you mean by grams:
0.159 mole x 60.08 g (Periodic table by adding both elements)
Cancel moles with moles (Original moles with the 1 mol at the bottom of the grams) and gives you:
9.55 grams of SiO2
I think its A because some scientist from the Department of Physics of Northeastern University found out that is not a part of Dalton's atomic theory.