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natali 33 [55]
3 years ago
7

Your calculated density of aluminum is d = 2.69 g/cm3. Aluminum’s accepted density is 2.70 g/cm3. Without writing the "%" sign,

calculate the percent error up to two decimal places:Your calculated density of aluminum is d = 2.69 g/cm3. Aluminum’s accepted density is 2.70 g/cm3. Without writing the "%" sign, calculate the percent error up to two decimal places:
Chemistry
2 answers:
Marina CMI [18]3 years ago
8 0

Answer:

0.4

Explanation:

The percent error, or relative error, is the error associated with a parameter, and it's the absolute error divided by the parameter.

The absolute error is the differece between the calculated value and the parameter (in module): |2.69 - 2.70| = 0.01 *100% = 1.0%.

The relative error is:

1.0%/2.70 = 0.37% = 0.4%

stepan [7]3 years ago
7 0

Answer:

0.37 %

Explanation:

Given that:

Calculated density of aluminum = 2.69 g/cm³

Accepted density of aluminum = 2.70 g/cm³

Error\ percentage=\frac {|Accepted\ value-Calculated\ value|}{Accepted\ value}\times 100

Thus, applying values as:

Error\ percentage=\frac {|2.70-2.69|}{2.70}\times 100

<u>Percent error = 0.37 %</u>

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Read 2 more answers
Use the periodic table and example bond table to answer the question.
lyudmila [28]

In keeping with the general trends, K-Br will have the smallest bond energy. The bond energy refers to the energy that keeps the atoms in a bond together.

<h3>What is bond energy?</h3>

Bond energy is the energy that is required to hold atoms together in a bond. This energy must also be supplied when the atoms are to be separated.

We have the bond energies of each of the bons in the question, we have to note that the the smallest value of bond energy is Na-Br hence in keeping with the general trends, K-Br will have the smallest bond energy.

Learn more about bond energies: brainly.com/question/14842720?

7 0
1 year ago
PLEASE HELP!!!!!!
pogonyaev

Answer:

m_{B}^{theoretical}=0.365gB

Y=87.1\%

Explanation:

Hello there!

In this case, since the reaction (A->B) have an initial amount of pure 4-aminobenzoic acid, the first step to compute the theoretical yield is to solve the following stoichiometric setup:

m_{B}^{theoretical}=0.303gA*\frac{1molA}{137.14gA}*\frac{1molB}{1molA}*\frac{165.19 gB}{1molB}\\\\   m_{B}^{theoretical}=0.365gB

Whereas A stands for 4-aminobenzoic acid and B for the benzocaine. Moreover, we compute the percent yield by dividing the actual yield (0.318 g) by the theoretical one (0.365 g):

Y=\frac{0.318g}{0.365g} *100\%\\\\Y=87.1\%

Best regards!

4 0
2 years ago
Which of the following acids is the WEAKEST? The acid is followed by its Ka value.HF, 3.5 × 10^-4HNO2, 4.6 × 10^-4HCN, 4.9 × 10^
Mila [183]

Answer:

HCN

Explanation:

There are several factors that can tell us when an acid is stronger than another, which are the following:

1. The Polarity of the X - H Bond

2. Size of the X atom.

3. Charge on the acid.

4. Oxidation state of the central atom

5. Values of Ka and pKa.

From all of this factors, we can see that the exercise is already giving us values of Ka, and also we have different types of acid, not only with the form H - X

So, we will base the force of an acid by it's pKa value.

The pKa value which is calculated with the expression:

pKa = -logKa

pKa is a value that indicates how strong is the acid you are working with. This value can vary depending on factors such the charge of the acid. I f this charge can be easily distributed in resonance structures, the compound is more acidic, and therefore the pKa value is lower.

The lower the pKa, the more acidic the compound is.

So calculating the pKa on every structure we have:

HF: pKa = -log(3.5x10^-4) = 3.46

HNO2: pKa = -log(4.6x10^-4) = 3.34

HCN: pKa = -log(4.9x10^-10) = 9.31

HCOOH: pKa = -log(1.8x10^-4) = 3.74

HClO2: -log(1.1x10^-2) = 1.96

So according to all this values, we can conclude that the weakest acid is the HCN

4 0
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