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GarryVolchara [31]
3 years ago
7

Which of the following statements must be true if the net force on an object is zero? Choose all that apply.

Physics
1 answer:
Black_prince [1.1K]3 years ago
5 0

Answer:

a) The object must have constant velocity.

d) The object must have zero acceleration.

Explanation:

We can solve the problem by using Newton's second law, which states that the net force acting on an object is equal to the product between mass and acceleration:

F = ma

where

F is the net force

m is the mass of the object

a is the acceleration

In this problem, the net force on the object is zero:

F = 0

This means that the acceleration of the object is also zero, according to the previous equation:

a = 0

So statement (d) is correct. Moreover, acceleration is defined as the rate of change of velocity:

a=\frac{\Delta v}{\Delta t}

Which means that \Delta v=0, so the velocity is constant. Therefore, statement (a) is also correct. The other two statements are false because:

b)The object must be at rest. --> false, the object can be moving at constant velocity, different from zero

c)The object must be at the origin. --> false, since the object can be in motion

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3 years ago
The maximum amount of static friction between this chair and the floor is 175 N. Which action would cause the chair to move to t
Amiraneli [1.4K]

Answer:

Applying 200 N of force to the chair from the right

Explanation:

6 0
3 years ago
By method of dimension show that the following equation are homogenous.
il63 [147K]

Answer:

Proof in explanataion

Explanation:

The basic dimensions are as follows:

MASS = M

LENGTH = L

TIME = T

i)

Given equation is:

H = \frac{u^2Sin^2\phi}{2g}

where,

H = height (meters)

u = speed (m/s)

g = acceleration due to gravity (m/s²)

Sin Ф = constant (no unit)

So there dimensions will be:

H = [L]

u = [LT⁻¹]

g = [LT⁻²]

Sin Ф = no dimension

Therefore,

[L] = \frac{[LT^{-1}]^2}{[LT^{-2}]}\\\\\ [L] = [L^{(2-1)}T^{(-2+2)}]

<u>[L] = [L]</u>

Hence, the equation is proven to be homogenous.

ii)

F = \frac{Gm_1m_2}{r^2}\\\\

where,

F = Force = Newton = kg.m/s² = [MLT⁻²]

G = Gravitational Constant = N.m²/kg² = (kg.m/s²)m²/kg² = m³/kg.s²

G = [M⁻¹L³T⁻²]

m₁ = m₂ = mass = kg = [M]

r = distance = m = [L]

Therefore,

[MLT^{-2}] = \frac{[M^{-1}L^{3}T^{-2}][M][M]}{[L]^2}\\\\\ [MLT^{-2}] = [M^{(-1+1+1)}L^{(3-2)}T^{-2}]\\\\

<u>[MLT⁻²] = [MLT⁻²]</u>

Hence, the equation is proven to be homogenous.

8 0
3 years ago
A standing wave of 603 Hz is produced on a string that is 1.33 m long and fixed on both ends. If the speed of the waves on this
kondaur [170]

Answer:

4.

Explanation:

Given,

frequency of standing wave = 603 Hz

length of string,L = 1.33 m

speed of the wave, v = 402 m/s

number of antinodes = ?

Wavelength of the standing wave

\lambda = \dfrac{v}{f}

\lambda = \dfrac{402}{603}

\lambda = 0.67\ m

Number of anti nodes in the standing wave

n=\dfrac{l}{\frac{\lambda}{2}}

n=\dfrac{2l}{\lambda}

n=\dfrac{2\times 1.33}{0.67}

n =3.97= 4.

Number of antinodes is equal to 4.

7 0
3 years ago
What is pH? (NEED ANSWER ASAP)
Pani-rosa [81]

Answer:

the answer is A

Explanation:

pH is a measure of how acidic/basic water

8 0
3 years ago
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