The work done is equal to the change in potential energy which is:
P.E = mgh
P.E = 500 x 9.81 x 15
P.E = 73,575 J

Power = work / time
Power = 73,575 / 20
Power = 3,700 Watts

5 0

4 years ago

A very long, solid insulating cylinder has radius R; bored along its entire length is a cylindrical hole with radius a. The axis

lawyer [7]

Answer:

The value of the electric field is $E_{net} = \dfrac{r \textbf{b}}{2\epsilon_{0}}$

Explanation:

We know that the electric field inside a solid cylinder at a distance $\textbf{r}$ from the centre is given by

$E = \dfrac{\rho \textbf{r}}{2 \epsilon_{0}}$

Let's consider the cross-section of the cylinder as shown in the figure. Let `O' be the centre of the long solid insulating cylinder having radius 'R'. Also consider that $O'$ be the cetre of the hole of radius 'a' situated at a distance 'b' from 'O'. Given, the volume charge density of the material is 'r'. So, the volume charge density inside the hole will be '-r'. Let's consider 'P' be any arbitrary point inside the hole situated at a distance 's' from $O'$ .

So, the electric field ' $E_{O}$ ' due to the long cylinder at point 'P' is given by

$E_{O} = \dfrac{r \textbf{c}}{2 \epsilon_{0}}$

and the electric field ' $E_{O'}$ 'due to the hole at point 'P' is given by

$E_{O'} = \dfrac{\rho \textbf{s}}{2 \epsilon_{0}}$

So the net electric field ( $E_{net}$ ) inside the hole is given by

$E_{net} = E_{O} - E_{O'} = \dfrac{r}{2\epsilon_{0}}(\textbf{c - s}) = \dfrac{r \textbf{b}}{2\epsilon_{0}}$

5 0

4 years ago

A man walks 400 m in the direction 45° north of east. Represent this vector graphically by

Marrrta [24]

Answer:

Explanation:

Coordinate system is one that describe the location of an object in a given plane. It implies the use of axes (coordinates) and points.

Given that the man in the question walks 400 m due north of east. The cardinal points can be used in this case, with the north and east cardinals as the required axis.

scale = $\frac{length on drawing}{original length}$

= $\frac{10}{400}$

= $\frac{1}{40}$

scale = 1:40

This is a reduced scale which implies that 1 cm on the drawing is equal to 40 m on the original length.

The man's direction is $45^{o}$ north of east.

The graphical drawing of the vector is herewith attached to this answer.

5 0

3 years ago