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zhuklara [117]
3 years ago
7

Imagine you transfer heat into a gas. This heat splits up in two different ways: Additional thermal energy making the gas hotter

and “fuel” for the gas to do work. Let’s suppose, 64% of the transferred heat transforms into thermal energy. How many percent of the initial heat can be used to do work?
Physics
1 answer:
navik [9.2K]3 years ago
7 0

Answer:

  • <u>36% of the initial heat can be used to do work.</u>

Explanation:

The initial heat is the 100%, i.e. it is all the heat that will be transferred.

It wil be transferred into two different kinds of energy:

  • additional thermal energy that will increase the thermal energy of the gas, making it hotter. Call it U. U = 64%. And,

  • "fuel" for the gas to do work. Call it W.

Then,

  • 100% = U + W
  • W = 100% - U
  • W = 100% - 64% = 36%

That is, 36% of the initial heat is available to do work.

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Which of these processes are chemical reactions
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Explanation:

  • In chemical reactions, chemical changes occur.
  • Atoms are simply rearranged and new bonds are formed.
  • Chemical reactions are driven by a need for atoms to attain stability in their structure.
  • In all chemical reactions, a reactant or reactants gives new product i.e new substances are formed.
  • Most these reactions are not easily reversible.
  • They are usually accompanied by the release of energy.

Learn more:

Chemical change brainly.com/question/9388643

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5 0
3 years ago
The resistivity of a metal increases slightly with increased temperature. This can be expressed as rho= rho0[1+α(T−T0)] , where
Stolb23 [73]

Answer:

At 81. 52 Deg C its resistance will be 0.31 Ω.

Explanation:

The resistance of wire =R_T =\frac{\rho_T \ l}{A}

Where R_T =Resistance of wire at Temperature T

\rho_T = Resistivity at temperature T =\rho_0 \ [1 \ + \alpha\ (T-T_0\ )]

Where T_0 =20\ Deg\ C , \  \rho_0 = Constant,  \alpha =3.9 \times 10^-^3 DegC^-1 \ (Given)

l=Length of the wire

& A = Area of cross section of wire

For long and thin wire the resistance & resistivity relation will be as follows

\frac{R_T_1}{R_T_2}=\frac{\rho_0(1+\alpha \cdot(T_1-2 0 )}{\rho_0(1+\alpha \cdot (T_2 -20 )}

\frac{0.25}{0.31}=\frac{1}{[1+\alpha(T-20)]}

1.24=1+\alpha (T-20)

0.24=\alpha(\ T -20 )

Putting\ the\ value\ of \alpha = 3.9 \times 10^-^3 DegC^-1

T = 81.52 Deg C

4 0
3 years ago
A stone is thrown vertically up. What kind of energy did the stone have initially? What happens to this energy as the stone asce
Alex

Answer:

kinetic energy at first

Explanation:

kinetic turns to potential as it gains height

7 0
3 years ago
I have 2 bulbs one coverts 60% of energy to light 45% which is the most efficient and what happens to the rest of the energy
Leya [2.2K]

Answer:

The first one (60%)

Explanation:

The first one converts 15% more energy than the other one. Therefore, it is more efficient.

Hope this helps!

5 0
3 years ago
Read 2 more answers
0.042 kg … ________________grams
olchik [2.2K]

Answer:

42 grams

Explanation:

you multiply the value by 1000 to get your answer

6 0
3 years ago
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