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zhuklara [117]
3 years ago
7

Imagine you transfer heat into a gas. This heat splits up in two different ways: Additional thermal energy making the gas hotter

and “fuel” for the gas to do work. Let’s suppose, 64% of the transferred heat transforms into thermal energy. How many percent of the initial heat can be used to do work?
Physics
1 answer:
navik [9.2K]3 years ago
7 0

Answer:

  • <u>36% of the initial heat can be used to do work.</u>

Explanation:

The initial heat is the 100%, i.e. it is all the heat that will be transferred.

It wil be transferred into two different kinds of energy:

  • additional thermal energy that will increase the thermal energy of the gas, making it hotter. Call it U. U = 64%. And,

  • "fuel" for the gas to do work. Call it W.

Then,

  • 100% = U + W
  • W = 100% - U
  • W = 100% - 64% = 36%

That is, 36% of the initial heat is available to do work.

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The waves that occur when you drop and stone into the water when skipping rocks
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3 years ago
A uniform stick 1.5 m long with a total mass of 250 g is pivoted at its center. A 3.3-g bullet is shot through the stick midway
Andru [333]

Answer:

<em>63.44 rad/s</em>

<em></em>

Explanation:

mass of bullet = 3.3 g = 0.0033 kg

initial velocity of bullet v_{1} = 250 m/s

final velocity of bullet v_{2} = 140 m/s

loss of kinetic energy of the bullet = \frac{1}{2}m(v^{2} _{1} - v^{2} _{2})

==> \frac{1}{2}*0.0033*(250^{2}  - 140^{2} ) = 70.785 J

this energy is given to the stick

The stick has mass = 250 g =0.25 kg

its kinetic energy = 70.785 J

from

KE = \frac{1}{2} mv^{2}

70.785 = \frac{1}{2}*0.25*v^{2}

566.28 = v^{2}

v= \sqrt{566.28} = 23.79 m/s

the stick is 1.5 m long

this energy is impacted midway between the pivot and one end of the stick, which leaves it with a radius of 1.5/4 = 0.375 m

The angular speed will be

Ω = v/r = 23.79/0.375 =<em> 63.44 rad/s</em>

5 0
3 years ago
Electricity seems like a fundamental element in the construction of any home. However, to have electricity run into and out of a
olganol [36]

Answer:

•Most of the components that make up curcuits are conductors. Electricity flows easily thought conductors such as metal or water.Electricity does not flow easily thought insulators such as wood or rubber.

•When a battery is used to power a circuit, the circuit the current must travel from one pole of the battery to the opposite battery.

•Resisotors show the flow of Electricity throught a circuit this can prevent components of the circuit from 'brning out'. In a curcuit diagram, resistors are represented by bending lines.

Explanation:

8 0
3 years ago
The radius of the thinner wire is 0.22 mm and the radius of the thick wire is 0.55 mm. There are 4.0 x 1028 mobile electrons per
Natasha_Volkova [10]

Answer:

0.2631 N/C

Explanation:

Given that:

The radius of the wire r = 0.22 mm = 0.22 × 10⁻³ m

The radius of the thick wire  r' = 0.55 mm = 0.55 × 10⁻³ m

The numbers of electrons passing through B, N = 6.0  × 10¹⁸ electrons

Electron mobility  μ =  6.0 x 10-4 (m/s)/(N/C)

= 0.0006

The number of electron flow per second is calculated as follows:

I = \frac{q}{t}

I = \frac{Ne}{t}

I = \frac{6*10^{18}(1.6*10^{-18})C}{1 \ s}

I = 0.96 \ A

The magnitude of the electric field is:

E = \frac{I}{ \mu n eA}

E = \frac{I}{ \mu n e(\pi r^2)}

E = \frac{0.96}{(0.0006 m/s N/C ) (4*10^{28})(1.6*10^{-19}C)(0.55*10^{-3}m)^2}

E = 0.2631 N/C

8 0
3 years ago
POSSIE
kotegsom [21]

Answer:

please find attached pdf

Explanation:

Download pdf
3 0
3 years ago
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