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zhuklara [117]
3 years ago
7

Imagine you transfer heat into a gas. This heat splits up in two different ways: Additional thermal energy making the gas hotter

and “fuel” for the gas to do work. Let’s suppose, 64% of the transferred heat transforms into thermal energy. How many percent of the initial heat can be used to do work?
Physics
1 answer:
navik [9.2K]3 years ago
7 0

Answer:

  • <u>36% of the initial heat can be used to do work.</u>

Explanation:

The initial heat is the 100%, i.e. it is all the heat that will be transferred.

It wil be transferred into two different kinds of energy:

  • additional thermal energy that will increase the thermal energy of the gas, making it hotter. Call it U. U = 64%. And,

  • "fuel" for the gas to do work. Call it W.

Then,

  • 100% = U + W
  • W = 100% - U
  • W = 100% - 64% = 36%

That is, 36% of the initial heat is available to do work.

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What is the displacement of the car between t=1s and t=4s
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Answer:

Option C. 30 m

Explanation:

From the graph given in the question above,

At t = 1 s,

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Thus, we can simply calculate the displacement of the car between t = 1 and t = 4 by calculating the difference in the displacement at the various time. This is illustrated below:

Displacement at t = 1 s (d1) = 10 m

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4 0
3 years ago
Need an answer, please need an answer, please​
Karolina [17]

9514 1404 393

Answer:

  • moderate low: 82
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  • vigorous low: 123
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Explanation:

When calculations are repetitive, I find it convenient to use a calculator that can work with tables.

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