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MatroZZZ [7]
3 years ago
6

What force is necessary to accelerate a 70-kg object at a rate of 4.2 m/s2 ? Show your wo k below?

Physics
1 answer:
Naily [24]3 years ago
4 0
Newton's 2nd law of motion:

         Force = (mass) x (acceleration)

                   = (70 kg) x (4.2 m/s²)

                   =  (70 x 4.2)   kg-m/s²

                   =      294 newtons .

A picture of my wok is attached below. 

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Object a travels in the +x-direction before hitting a stationary object
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The object’s resultant angle of motion with the +x-axis after the collision is 47°

<span>From object A:
 
1) x-momentum is 5.7 × 10^4 kilogram meters/second,
2) y-momentum is 6.2 × 10^4 kilogram meters/second.
 
Now, we know, tan</span>Ф = \frac{y}{x}

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A container of rocks is brought back from the Moon's surface where the acceleration due to gravity is 162 meters per second if t
spin [16.1K]

Answer:

6318 N

Explanation:

From the question given above, the following data were obtained:

Acceleration due to gravity of the moon (gₘ) = 1.62 m/s²

Mass (m) of container = 650 kg

Weight (W) of container on the earth =.?

Next, we shall determine the acceleration due to gravity of the earth. This can be obtained as follow:

Acceleration due to gravity of the moon (gₘ) = 1.62 m/s²

Acceleration due to gravity of the earth (gₑ) =.?

gₘ = 1/6 × gₑ

1.62 = 1/6 × gₑ

1.62 = gₑ /6

Cross multiply

gₑ = 1.62 × 6

gₑ = 9.72 m/s²

Finally, we shall determine the weight of the container on the earth as follow:

Mass (m) of container = 650 kg

Acceleration due to gravity of the earth (gₑ) = 9.72 m/s²

Weight (W) of container on the earth =.?

W = m × gₑ

W = 650 × 9.72

W = 6318 N

Therefore, the weight of the container on earth is 6318 N

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