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ValentinkaMS [17]

3 years ago

5

If the average distance between bumps on a road is about 10 m and the natural frequency of the suspension system in the car is a

bout 0.90 hz, at what speed will you feel the bumps the most?

1 answer:

Mnenie [13.5K]3 years ago

3 0

When you hit a bump every 0.9 seconds.

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What is the purpose of the ism/wlan indicator light on the backplane of the router? what does it refer to?

ikadub [295]

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3 years ago

A 1502.7 kg car is traveling at 33.1 m/s when

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By definition of average acceleration,

<em>a</em> = (20 m/s - 33.1 m/s) / (4.7 s) ≈ -2.78 m/s²

Vertically, the car is in equilibrium, so the net force is equal to the friction force in the direction opposite the car's motion:

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If you just want the magnitude, drop the negative sign.

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2 years ago

A NASA satellite has just observed an asteroid that is on a collision course with the Earth. The asteroid has an estimated mass,

Citrus2011 [14]

Answer:

v = 7934.2 m/s

Explanation:

Here the total energy of the Asteroid and the Earth system will remains conserved

So we will have

$-\frac{GMm}{r} + \frac{1}{2}mv_0^2 = -\frac{GMm}{R} + \frac{1}{2}mv^2$

now we know that

$v_0 = 660 m/s$

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$m = 5 \times 10^9 kg$

$r = 4 \times 10^9 m$

$R = 6.37 \times 10^6 m$

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now we have

$2GM(\frac{1}{R} - \frac{1}{r}) + v_0^2 = v^2$

now plug in all data

$2(6.67 \times 10^{-11})(5.98 \times 10^{24})(\frac{1}{6.37 \times 10^6} - \frac{1}{4 \times 10^9}) + (660)^2 = v^2$

$v = 7934.2 m/s$

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2 years ago

Greg drew a diagram to compare two of the fundamental forces.

Mashcka [7]

Answer:

X: Always attractive

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