The engine efficiency is 64.73 %
<u>Explanation:</u>
Given data
To find the engine’s efficiency we have the formula,
Energy input- 4565 KJ
Energy output - 2955KJ
Efficiency= energy output/ energy input ×100%
=2955/4565
=0.6473 ×100
η =64.73 %
The engine efficiency is 64.73 %
CR < CY < CB
<h3>Which factors affect the critical angle for a given pair of media?</h3>
The factors which affect the critical angle are
(a) The colour (or wavelength) of light
(b) The temperature
(i) Effect of colour of light: The critical angle for a pair of media is less for the violet light and more for the red light. Thus the critical angle increases with the increase in wavelength of light.
(ii) Effect of temperature: The critical angle increases with increase in temperature because on increasing temperature of medium, its refractive index decreases.
According to the question,
μ 1 sinCR =1
μ 2 sinCY =1
μ 3 sinCB =1
μ 1 > μ 2 and μ 2 > μ 3
⟹μ 1 > μ 2 > μ 3
CR < CY < CB
Thus,
The critical angle increases with the increase in wavelength of light.
Learn more about wavelength of light here:
brainly.com/question/27557868
#SPJ1
Answer:
1) 460.5 N
2) 431.7 N
Explanation:
Draw a free body diagram. There are four forces on the hammer:
Applied force 62.5 N in the +x direction, 30 cm from the ground
Reaction force Rᵧ in the +y direction, at the point of contact
Reaction force Rₓ in the +x direction, at the point of contact
Reaction force F at 31° from the vertical, 4.75 cm to the left of the point of contact
Part One
To find F, sum the moments about the point of contact:
∑τ = Iα
(62.5 N) (30 cm) − (F cos 31°) (4.75 cm) = 0
F = 460.5 N
Part Two
To find Rₓ and Rᵧ, sum the forces in the x and y directions.
∑Fₓ = ma
62.5 N − F sin 31° + Rₓ = 0
Rₓ = 174.7 N
∑Fᵧ = ma
-F cos 31° + Rᵧ = 0
Rᵧ = 394.7 N
The net reaction force at the point of contact is:
R = √(Rₓ² + Rᵧ²)
R = 431.7 N
Answer:
An acid is a compound that increases hydrogen ions (H+) when it is dissolved in a solution.
all I got
from kinematics equation if we know that final speed is ZERO and initial speed is given that due to constant deceleration the object will stop in some distance "d" and this distance can be calculated by kinematics
here acceleration due to friction will be same at all different speed
so for 45 km/h speed the distance of stop is 15 m
while at other speed 112.5 km/h the distance will be unknown
now we will have
now divide above two equations
So it will stop in distance 93.75 m
