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ValentinkaMS [17]
3 years ago
5

If the average distance between bumps on a road is about 10 m and the natural frequency of the suspension system in the car is a

bout 0.90 hz, at what speed will you feel the bumps the most?
Physics
1 answer:
Mnenie [13.5K]3 years ago
3 0
When you hit a bump every 0.9 seconds.
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2. Three super strong teenagers pull a heavy crate across the floor. Dion pulls with a force of 18.5 N towards 0°. Shirley pulls
kogti [31]

Answer:

A) The resultant force is 43.4 [N]

B) The movement of the heavy crate is going to the right and in the negative direction on the y-axis

Explanation:

We need to make a sketch of the different forces acting on the heavy crate.

In the attached image we can see the forces and the sum of the vector with their respective angles.

Forces in the X-axis

Fdionx=18.5N\\\\Fshix=16.5*cos(30)=14.29N\\Fjoanx=19.5*cos(60)=9.75N\\\\Forcex= 18.5 + 14.29 + 9.75 = 42.54 N

Forces in the y-axis

FDiony=0[N]\\Fshirley= 16.5*sin(30)=8.25[N]\\Fjoany=19.5*sin(60)=16.88 [N]\\\\Forcesy=0+8.25-16.88= -8.63[N]

Using the Pythagorean theorem

Tforce=\sqrt{(42.54)^{2} +(8.63)^{2} } \\\\Tforce= 43.4N

The movement of the heavy crate is going to the right and in the negative direction on the y-axis, this can be easily seen in the graphical sum of vectors.

8 0
3 years ago
Explain the relationship between the earth's crust and the earth's ocean sizes.
valina [46]

the outermost layer of Earth’s lithosphere that is found under the oceans and molded at scattering centres ono ceanic ridges, which occur at deviating plate boundaries

Oceanic crust is about 6 km (4 miles) thick.

hope it helps

3 0
3 years ago
how would the velocity of the book change if the applied force were equal to the sliding friction force
Inessa [10]
Yes, Sliding friction opposes the movement of the book, slowing it down.sliding That's the 'kinetic' kind.. According to Newton's second law, F=ma. That is, the bear's acceleration should be proportional to the total force acting on the bear. As the bear's velocity is constant, its acceleration is zero. Therefore, the total Force acting on the bear is zero. Thus, the friction has to be equal in magnitude and opposite in direction to the bear's weight. As W=mg, we get that its weight is  <span>9.8*400=3,920 Newton. Thus, the friction acting on the bear is 3,920 Newton</span>
3 0
3 years ago
A swimmer, capable of swimming at a speed of 1.0 m/s in still water (i.e., the swimmer can swim with a speed of 1.0 m/s relative
Vesnalui [34]
If the current takes him downstream we must find the resultant vector of the velocities: V res= \sqrt{1^{2}+0.91^{2}  } = \sqrt{1.8281}= 1.3520747 Then if the river is 3000 m-wide the swimmer will have to pass:
 1.3520747 · 300 = 4056.14 m                t = 4056.14 m : 1 m/s
a ) It takes 4056.15 seconds ( 1 hour 7 minutes and 36 seconds ) to cross the river.  
b ) 0.91 · 3000 = 2730 m
He will be 2730 m downstream.
5 0
3 years ago
How are sound waves different from the ripples that spread across water?​
prisoha [69]

Answer:

.

Explanation:

Sound waves are caused by vibration ripples in water are caused by disturbance in the molecules

6 0
3 years ago
Read 2 more answers
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