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Sidana [21]
3 years ago
15

Determine the order pair and quadrant for each point: A. B. C.

Mathematics
1 answer:
Taya2010 [7]3 years ago
4 0

Answer:

A: (-4,1) QUAD 2

B: (-1, -3) QUAD 3

C: (2,5) QUAD 1

D: (5, -4) QUAD 4

Step-by-step explanation:

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Dafna11 [192]

Answer:

6

explanation

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3 years ago
Graph the linear equation 5x - 6y =60
Alex73 [517]
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Ok here it is.. the question (´・ω・`) please leave a detailed explanation of how you got your CORRECT and APPROPRIATE answer plz!
romanna [79]

Answer:

ok this is better

Step-by-step explanation:

1 A

2 D

3 B

4 C

5 A

6 C

7 B

8 D

9 A

10 C

11 B

12 D

13 A

14 A

15 D

16 B

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3 0
3 years ago
Read 2 more answers
A magazine conducts an annual survey in which readers rate their favorite cruise ship. All ships are rated on a 100-point scale,
Lyrx [107]

Answer:

a) The point of estimate for \mu_1 -\mu_2 is just given by:  

\bar X_1 -\bar X_2 =85.82-81.90=3.92  

b) SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975  

And the Margin of error is given by:

Me= z_{\alpha/2} * SE=1.96*0.975=1.910

c) The 95% confidence interval would be given by 2.009 \leq \mu_1 -\mu_2 \leq 5.83.

Step-by-step explanation:

Notation and previous concepts

n_1 =35 represent the sample of ships that carry fewer than 500 passengers

n_2 =44 represent the sample of ships that carry 500 or more passengers

\bar x_1 =85.82 represent the mean sample of of ships that carry fewer than 500 passengers

\bar x_2 =81.90 represent the mean sample of of ships that carry 500 or more passengers

\sigma_1 =4.55 represent the population deviation of ships that carry fewer than 500 passengers

\sigma_2 =3.97 represent the sample deviation of ships that carry 500 or more passengers

\alpha=0.05 represent the significance level

Confidence =95% or 0.95

The confidence interval for the difference of means is given by the following formula:  

(\bar X_1 -\bar X_2) \pm z_{\alpha/2}\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})} (1)  

Part a

The point of estimate for \mu_1 -\mu_2 is just given by:  

\bar X_1 -\bar X_2 =85.82-81.90=3.92  

Part b: At 95% confidence, what is the margin of error?

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-NORM.INV(0.025,0,1)".And we see that z_{\alpha/2}=1.96  

The standard error is given by the following formula:  

SE=\sqrt{(\frac{\sigma^2_1}{n_1}+\frac{\sigma^2_2}{n_2})}  

And replacing we have:  

SE=\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=0.975  

And the Margin of error is given by:

Me= z_{\alpha/2} * SE=1.96*0.975=1.910

Part c: What is a 95% confidence interval estimate of the difference between the population mean ratings for the two sizes of ships?

Confidence interval  

Now we have everything in order to replace into formula (1):  

3.92-1.96\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=2.009  

3.92+1.96\sqrt{(\frac{4.55^2}{35}+\frac{3.97^2}{44})}=5.830  

So on this case the 95% confidence interval would be given by 2.009 \leq \mu_1 -\mu_2 \leq 5.83.

7 0
3 years ago
(-1,4) and ( 1, -1) Find the distance between each pair of points
Nikolay [14]

Answer:

\sqrt{29}

Step-by-step explanation:

We are basically trying to find the hypotenuse of the triangle.

The distance between the x is 2, and the distance between the y is 5, which makes a length and a width.

Pythagrenum theorem: a^2+b^2=c^2

2^2 is 4, 5^2 is 25.

4+25 is 29.

The distance is \sqrt{29}.

8 0
3 years ago
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