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4 years ago

Explain how the periodic table can help in writing electron configurations

2 answers:

4 0

The periodic table can help in writing electron configurations because on the periodic table, you might notice a number in the top right corner, this tells you how much electrons are in the specific element....please mark brainliest!

Vinil7 [7]4 years ago

3 0

Look At the bottom number

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Which is the first stage of mitosis? A.anaphase B.prophase C.metaphase D.telophase

sineoko [7]

I think is B. Prophase:)

4 0

3 years ago

Read 2 more answers

Identify and name the functional present in (i) C₂ H₂ (ii). CH₃ CH₂OH.

Minchanka [31]

Answer:

I)Acetylene

II)2-Methyl-1-butanol

Explanation:

I)appears as a colorless gas with a faint garlic-like odor. Easily ignited and burns with a sooty flame. Gas is lighter than air.

6 0

3 years ago

What would be considered the reactant(s) in H2 + O2 <-> H2O

jeka94

Answer:

H2+ 02

Explanation:

becuase those 2 are at the beginning of the equation and in front of the equilibrium sign :)

6 0

4 years ago

Electrons found in the outside energy level are?

sergij07 [2.7K]

Answer:

valance electrons

Explanation:

these are the electrons in the outermost shell

4 0

4 years ago

Read 2 more answers

Read the given equation. 2Na + 2H2O → 2NaOH + H2

Crank

Answer:

B) 12.9 grams.

Explanation:

How many moles of molecules in that 6.30 L of H₂?

The volume of one mole of an ideal gas at STP (0 °C, 1 atm) is 22.4 liters.

(The volume of that one mole of gas at STP will be 22.7 liters if STP is defined as 0 °C and 10⁵ Pa).

$\displaystyle n(\text{H}_2) = \frac{6.30\;\text{L}}{22.4\;\text{L}\cdot\text{mol}^{-1}} = 0.28125\;\text{mol}$ .

How many moles of Na will be needed?

The coefficient in front of Na in the equation is twice the coefficient in front of H₂. It takes two moles of Na to produce one mole of H₂.

$n(\text{Na}) = 2\;n(\text{H}_2) = 2\times 0.28125= 0.5625\;\text{mol}$ .

What's the mass of that many Na atoms?

Refer to a modern periodic table. The molar mass of ₁₁Na is 22.990. The mass of one mole of Na atoms is 22.990 gram. The mass of 0.5625 moles of Na atoms will be

$m = n\cdot M = 0.5625 \times 22.990 = 12.9\;\text{g}$ .

(2 sig. fig. as in the volume of the H₂ gas.)

6 0

3 years ago