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nlexa [21]
3 years ago
7

If the equilibrium constant of the reaction is 0.85, then which statement is true if the mass of A is 10.5 grams; the density of

B is 0.82 g/ml; the concentration of C is 0.64 M; and the concentration of D is 0.38 M.
A(s) + 3 B(l) _____ 2(aq) + D(aq)
Pick the correct statement about this system.
A. Q < K and reaction shifts left
B. Q > K and reaction shifts left
C. Q > K and reaction shifts right
D. Q = K and reaction does not shift
E. Q < K and reaction shifts right
Chemistry
1 answer:
snow_tiger [21]3 years ago
8 0

Answer:

E. Q < K and reaction shifts right

Explanation:

Step 1: Write the balanced equation

A(s) + 3 B(l) ⇄ 2(aq) + D(aq)

Step 2: Calculate the reaction quotient (Q)

The reaction quotient, as the equilibrium constant (K), only includes aqueous and gaseous species.

Q = [C]² × [D]

Q = 0.64² × 0.38

Q = 0.15

Step 3: Compare Q with K and determine in which direction will shift the reaction

Since Q < K, the reaction will shift to the right to attain the equilibrium.

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amid [387]

Answer:

C

Explanation:

7 0
3 years ago
The molecular mass of methyl ethanoate is 75.1 amu . calculate the molecular mass of propanoic acid, an isomer of methyl ethanoa
iren [92.7K]
Molecular Formula of Propanoic Acid is....

                                                C₃H₆O₂
Where;

Atomic Mass of C  =  12

Atomic Mass of H  =  1

Atomic Mass of O  =  6

Substituting Atomic Masses in molecular formula,

                                                (12)₃ + (1)₆ + (16)₂

                                                   36  +  6  +  32

                                                        74 g/mol

Result:
            
Molecular Mass of Propanoic Acid is 74 g/mol. Structure of Methyl Ethanoate and Propanoic Acid are as follow,

7 0
4 years ago
3.01 × 1023 molecules H2O
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3079.23 is what you get when you multiply the answers.
6 0
3 years ago
Which agency publishes the food code
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4 0
4 years ago
A 1 mol sample of gas has a temperature of 225K, a volume of 3.3L, and a pressure of 500 torr. What would the temperature be if
serg [7]
<h3>Answer:</h3>

78.75 K

<h3>Explanation:</h3>

<u>We are given;</u>

  • Initial pressure, P₁ = 500 torr
  • Initial temperature,T₁ = 225 K
  • Initial volume, V₁ = 3.3 L
  • Final volume, V₂ = 2.75 L
  • Final pressure, P₂ = 210 torr                        

We are required to calculate the new temperature, T₂

  • To find the new temperature, T₂ we are going to use the combined gas law;
  • According to the combined gas law;

P₁V₁/T₁ = P₂V₂/T₂

We can calculate the new temperature, T₂;

Rearranging the formula;

T₂ =(P₂V₂T₁) ÷ (P₁V₁)

  = (210 torr × 2.75 L × 225 K) ÷ (500 torr × 3.3 L)

  = 78.75 K

Therefore, the new volume of the sample is 78.75 K

5 0
4 years ago
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