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saw5 [17]
3 years ago
14

Use the drawing tool(s) to form the correct answer on the provided number line.

Mathematics
1 answer:
Nat2105 [25]3 years ago
7 0

Answer:

j=42.36

Step-by-step explanation:

=15 to original answer

You might be interested in
Find the distance and midpoint for the points (5,5) and (1,2).
stealth61 [152]

Answer:

midpoint = (3,3.5)

distance = 5

Step-by-step explanation:

midpoint = (x1+X2/2, y2+y2/2)

=(5+1/2, 5+2/2)

=(6/2, 7/2)

=(3, 3.5)

distance= √(x2-x1)^2 -(y2-y1)^2

=√(1-5)^2 -(2-5)^2

= √ 16+9 =√25 =5

5 0
2 years ago
7. What is the value of x for the triangle drawn below?
slega [8]

Answer:

where is the triangle?

8 0
3 years ago
The set of points (-3, 4), (-1, 1), (-3,-2), and (-5,1) identifies the vertices of a quadrilateral. Which is the most specific d
KIM [24]

Answer:

Option (4). Rhombus

Step-by-step explanation:

From the figure attached,

Distance AB = \sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2}

                     = \sqrt{(1-4)^2+(-5+3)^2}

                     = \sqrt{(-3)^2+(-2)^2}

                     = \sqrt{13}

Distance BC = \sqrt{(4-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance CD = \sqrt{(-2-1)^2+(-3+1)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Distance AD = \sqrt{(1+2)^2+(-5+3)^2}

                     = \sqrt{9+4}

                     = \sqrt{13}

Slope of AB (m_{1}) = \frac{y_{2}-y_{1}}{x_{2}-x_{1}}

                           = \frac{4-1}{-3+5}

                           = \frac{3}{2}

Slope of BC (m_{2}) = \frac{4-1}{-3+1}

                            = -\frac{3}{2}

If AB and BC are perpendicular then,

m_{1}\times m_{2}=-1

But it's not true.

[m_{1}\times m_{2}=(\frac{3}{2})(-\frac{3}{2}) = -\frac{9}{4}]

It shows that the consecutive sides of the quadrilateral are not perpendicular.

Therefore, ABCD is neither square nor a rectangle.

Slope of diagonal BD = \frac{4+2}{-3+3}

                                    = Not defined (parallel to y-axis)

Slope of diagonal AC = \frac{1-1}{-1+5}

                                    = 0 [parallel to x-axis]

Therefore, both the diagonals AC and BD will be perpendicular.

And the quadrilateral formed by the given points will be a rhombus.

5 0
3 years ago
Solve for x.
Delicious77 [7]

Answer:

134+144

Step-by-step explanation:

just take the answer (278)- the number they give you

278-

134

144

6 0
3 years ago
Read 2 more answers
What is the value of 3xy+5x-y/2 if x=12 and y=8
ExtremeBDS [4]
3(12)(8)+5(12)-(8)/2
3(96)+60-8/2
298+62/2
298+31=329
your answer is 329
3 0
3 years ago
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