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Phantasy [73]
3 years ago
15

Writing Proportions.

Mathematics
2 answers:
Pavlova-9 [17]3 years ago
7 0
Answer: A
If you solve it you get $6.40
It makes sense
Bas_tet [7]3 years ago
5 0

Answer: A

Step-by-step explanation:

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HELP MARK BRANLIEST AND ALSO POINTS
Taya2010 [7]

Answer:

25 rides

Step-by-step explanation:

has $28.50

15.75 + 0.50r \leq 28.50

Subtract 15.75

0.50r \leq 12.75

r \leq 25.5

you can't have half rides, so 25 rides

4 0
3 years ago
Suppose the heights of professional horse jockeys are normally distributed with a mean of 62 in. and a standard deviation of 2 i
ch4aika [34]
Mean = 62 in
SD = 2 in

At 16% = 0.16 and using Z tables,

Z≈ -0.99

x =(-0.99*2) + 62 ≈ 60 in

This represents jockeys who are shorter than 60 in.
6 0
3 years ago
PLEASE HELP WILL GIVE A BRAINLIEST!!
Tanya [424]
The answer is a. number of boys < 89.
7 0
3 years ago
Read 2 more answers
Hey can you please help me posted picture of question
Bess [88]
The answer is C. hope this helps.

7 0
3 years ago
Read 2 more answers
What is quartile 1 (Q1)quartile 3 (Q3) and the IQR? Answer all three parts . 13, 23, 24, 25, 26, 26, 37, 47, 47, 48, 50
Fittoniya [83]

Answer:

Quartile 1 (Q1) = 24

Quartile 2 (Q2) = 47

IQR = 23

Step-by-step explanation:

Given:

The set of data are:

13, 23, 24, 25, 26, <u>26</u>, 37, 47, 47, 48, 50

The data are in increasing order. The number terms are, n = 11.

Therefore, the middle term = \frac{n+1}{2}=\frac{11+1}{2}=6^{th}\ term

So, the median = 26

Now, the median divides the set of data into two parts. The median of first part is the quartile 1 and the median of second part is quartile 2.

So, the first part has the following terms:

13, 23, <u>24</u>, 25, 26

Here also, n=5. So, the third term is the median.

∴ Q1 = 24

The second part has the following terms:

37, 47, <u>47</u>, 48, 50

Here also, n=5. So, the third term is the median.

∴ Q2 = 47.

Now, IQR = Q2 - Q1 = 47 - 24 = 23.

7 0
3 years ago
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