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makkiz [27]
3 years ago
10

Solve the following inequality. Then place the correct answer in the box provided. Answer in terms of a mixed number.

Mathematics
2 answers:
Mama L [17]3 years ago
5 0
2P + 2 + 3P + 6 > 2
5P + 8 > 2
Subtract 8 from both sides.
5P > -6
Divide each side by 5.
P > -6/5
drek231 [11]3 years ago
3 0

Answer: -1\frac{1}{5}

Step-by-step explanation:

2(P +1) + 3(P + 2 ) > 2

Distribute 2 and 3

2P+2+3P+6>2

Combine like terms;

5P+8>2

Subtract 8

5P>2-8

5P>-6

Divide by 5

P>-\frac{6}{5}

Convert to a mixed number by dividing. However, when we have the numerator greater than the denominator, we must find a way to make the numerator lower. We can achieve this by separating it into 2 fractions.

-\frac{6}{5}=-\frac{5}{5}-\frac{1}{5}

When we do this, we can see that 5/5 = 1

-1-\frac{1}{5}=-1\frac{1}{5}

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A store has a 20% off discount. If the original price of a shirt is $48, how<br> much will you pay?
Nikitich [7]

Answer:$38.70

Step-by-step explanation:

20% = 5

48 / 5 = 9.6

20% = $9.60

48 - 9.6 = $38.7

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3 years ago
The figure is a rectangular prism. Identify which one of the line segments in the given figure is perpendicular to . HG
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If f(x) is differentiable for the closed interval [-1, 4] such that f(-1) = -3 and f(4) = 12, then there exists a value c, -1 &l
masha68 [24]

Answer:

  A)  f'(c) = 3

Step-by-step explanation:

The mean value theorem says that if f(x) is continuous on the closed interval [a, b] and differentiable on the open interval (a, b), then there exists some c such that ...

  a < c < b

  f'(c) = (f(b) -f(a))/(b -a)

__

We are told that f(x) is differentiable on the closed interval [-1, 4], so we know it meets the requirements of the mean value theorem. Then we can conclude that there is some c such that ...

  f'(c) = (12 -(-3))/(4 -(-1)) = 15/5

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4 0
3 years ago
How do you do this problem?
umka2103 [35]

Answer:

Step-by-step explanation:

You are going to work entirely on the right, until you can compare what is on the right with what you are given on the left.

a/1 + b/(x + 2) + c/(x - 8)

The first step is to determine the common denominator which is

(x + 2)(x - 8)

Now put each fraction over the common denominator.

<u>a(x + 2)(x - 8) + b(x - 8) + c(x + 2)</u>

             (x + 2)(x - 8)

The denominators on the left and right are the same, so you need only work with the numerators.

Remove the brackets.

a(x^2 - 6x - 16) + bx - 8b + cx + 2c

ax^2 - 6ax - 16a + bx - 8b + cx + 2c

In that whole expression, there is only 1 term that has an x^2 in it and that is the very first term.

a = 2 when you compare it to the left. You do this so you can get a value for  a.

Now put a = 2 in the first three terms on the expression above

2x^2 - 6*2x - 16(2) + bx - 8b + cx + 2c

2x^2 - 12x - 32 + bx - 8b + cx + 2c

The next thing is to get all the terms containing x together.

-12x + bx + cx = - 14x That's the term on the left (-14x). Divide by x

-12 + b + c = - 14          Add 12 to both sides

b + c = -14 + 12

b + c = - 2                    (x)

======================

Now you equate the terms with no x's in them.

-32 - 8b + 2c = - 76      Add 32 to both sides.

-8b + 2c = - 76 + 32

-8b + 2c = - 44             Divide by 2

-4b + c = - 22               (y)

Subtract (y) - (x)

-4b + c = - 22

 <u> b + c = - 2</u>

- 5b = - 20                   Divide by - 5

-5b/-5 = - 20/-5

b = 4

==============

b + c = - 2                     Find c substitute b = 4

4 + c = - 2                     Subtract 4 from both sides

c = - 2 - 4

c = - 6      

===============  

Answer

a = 2

b = 4

c = -6

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3 years ago
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morpeh [17]

Answer:

40%

Step-by-step explanation:

brainliest please

7 0
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