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Maksim231197 [3]

3 years ago

11

If f(x) = -9x +9 and g(x)+squroot x+1, what is (f degree sign g) 24

1 answer:

Leno4ka [110]3 years ago

7 0

(f ° g) (x) means the composition of the two functions in this order f (g (x) )

So, given f(x) = - 9x + 9 and g(x) = √(x + 1), you must do this:

f(g(x)) = - 9 [ g(x) ] + 9 = - 9 [√(x+1) ] + 9 => f(g(24) = - 9 √(24 + 1) + 9 = - 9√25 + 9 =

= -9(5) + 9 = -45 + 9 = - 36

Answer: - 36

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Add these fractions just pretend / means fraction

CaHeK987 [17]

Answer is 16 1/3. hope that helps

8 0

3 years ago

a rectangular pool is 20 ft wide and 50 ft long. the deck is the same width all the way around the pool. the total area of the d

Alex

First, we need to get the total area of the rectangular pool.
Area = l * w
Area = 20 ft * 50 ft
Area = 1000 ft^2

Then the deck is 456 ft^2 with the width of 20ft, the same as the rectangular pool.

Area = l * w
456 = l * 20
l = 456 / 20
l = 22.8 ft.

So the walkway is 22.8ft wide.

3 0

3 years ago

VARVARA [1.3K]

Step-by-step explanation:

<u>Substitute x = -3, y = -3 into the </u><u>g</u><u>i</u><u>v</u><u>e</u><u>n</u><u> </u><u>equation:</u>

$- 3 + 4( - 3) = - 3$

<u>Simplify and Solve:</u>

$- 3 + - 12 \neq - 3$

The point (-3, -3) doesn't satisfy the given equation.

6 0

2 years ago

If 25 × 26 = n then which divison equation is also true

Ne4ueva [31]

Answer:

Option (A) in correct.

Step-by-step explanation:

Divide by $26$ on both the sides.

$\dfrac{25\times 26}{26}=n\div26\\25=n\div26$

3 0

2 years ago

Write an equation of a parabola in vertex form. Vertex (2,-3) and passes through (0,5)

Strike441 [17]

The parabola equation in vertex form passes through (0,5) is $y=2(x-2)^{2}-3$

<u>Solution:</u>

Given that, vertex of a parabola is (2,-3) and the parabola passes through the point (0, 5)

We have to find the equation of parabola in vertex form.

<em><u>The general form of parabola equation in vertex form is given as:</u></em>

$y=a(x-h)^{2}+k$

Where (h, k ) is vertex and "a" is a constant

Here in our problem, h = 2 and k = - 3

By substituting the values in general form we get,

$\begin{array}{l}{y=a(x-2)^{2}+(-3)} \\\\ {\rightarrow y=a(x-2)^{2}-3}\end{array}$

Now, we know that it passes through (0, 5). So substitute x = 0 and y = 5

$\begin{array}{l}{\rightarrow 5=a(0-2)^{2}-3} \\\\ {\rightarrow a(-2)^{2}=5+3} \\\\ {\rightarrow 4 a=8} \\\\ {\rightarrow a=2}\end{array}$

So substituting the value of "a" we get,

$y=2(x-2)^{2}-3$

Hence, the parabola equation in vertex form is $y=2(x-2)^{2}-3$

5 0

3 years ago