I hope it's helpful for u but I am not sure my answer is right !
Answer:
66
Step-by-step explanation:
multiply everything together
Answer:
the first slot is 6.3 and the second is 14.7
Step-by-step explanation:
you divide 10.5 and 5 to find out how many trees you need to build one cabin. when you divide them, you get 2.1. you then multiply 2.1 to how ever many cabins are being built
Answer:
a) |n -11| = 5
b) n ∈ {6, 16}
Step-by-step explanation:
The wording of the question is ridiculous. We assume it is intended to read, "The distance between two numbers is 5. One of the numbers is 11. What are the possibilities for the other?"
a) The distance between a number (n) and 11 can be written as ...
|n -11|
Since we want that distance to be 5, we can write the equation ...
|n -11| = 5
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b) The equation resolves to two:
Adding 11 to both sides of both equations gives ...
The two solutions are n=6 and n=16.
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<em>Comment on the question statement</em>
Increasingly, we see curriculum materials written in Pidgin English or where the words have a meaning different from that understood by a native English speaker. It appears you are the lucky recipient of such materials, so must do occasional "interpretation". Here, it seems that "two time a number" is intended to mean "two numbers."
Answer:
92 attendees had activity cards
Step-by-step explanation:
Let x be the number of students with activity cards. Then 130-x is the number without, and the total revenue is ...
7x +10(130 -x) = 1024
7x +1300 -10x = 1024 . . . . eliminate parentheses
-3x = -276 . . . . . . . . . . . . . collect terms; subtract 1300
x = 92 . . . . . . divide by 3
92 students with activity cards attended the dance.
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<em>Comment on the solution</em>
Often, you will see such a problem solved using two equations. For example, they might be ...
Let 'a' represent the number with an activity card; 'w' the number without. Then ...
- a+w = 130 . . . . the total number of students
- 7a +10w = 1024 . . . . the revenue from ticket sales
The problem statement asks for the value of 'a', so you want to eliminate w from these equations. You can do that using substitution. Using the first equation to write an expression for w, you have ...
w = 130-a
and making the substitution into the second equation gives ...
7a +10(130 -a) = 1024
This should look a lot like the equation we used above. There, we skipped the extra variable and went straight to the single equation we needed to solve.
