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3 years ago

If f(x) = -9x +9 and g(x)+squroot x+1, what is (f degree sign g) 24

1 answer:

7 0

(f ° g) (x) means the composition of the two functions in this order f (g (x) )

So, given f(x) = - 9x + 9 and g(x) = √(x + 1), you must do this:

f(g(x)) = - 9 [ g(x) ] + 9 = - 9 [√(x+1) ] + 9 => f(g(24) = - 9 √(24 + 1) + 9 = - 9√25 + 9 =

= -9(5) + 9 = -45 + 9 = - 36

Answer: - 36

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If a mole of sodium chloride weighs approximately 58 grams, and you have 29 grams of sodium chloride, how many moles of sodium c

Alexus [3.1K]

The answer is A.0.5 moles

a mole of sodium chloride weighs approximately 58 grams: 1 M - 58 g
you have 29 grams of sodium chloride, how many moles of sodium chloride do you have: xM - 29g

1 M : 58g = x : 29 g
x = 1 M : 58g * 29 g = 0.5 M

7 0

2 years ago

Factor f(x) = 15x^3 - 15x^2 - 90x completely and determine the exact value(s) of the zero(s) and enter them as a comma separated

Illusion [34]

Answer:

$x=-2,0,3$

Step-by-step explanation:

We have been given a function $f(x)=15x^3-15x^2-90x$ . We are asked to find the zeros of our given function.

To find the zeros of our given function, we will equate our given function by 0 as shown below:

$15x^3-15x^2-90x=0$

Now, we will factor our equation. We can see that all terms of our equation a common factor that is $15x$ .

Upon factoring out $15x$ , we will get:

$15x(x^2-x-6)=0$

Now, we will split the middle term of our equation into parts, whose sum is $-1$ and whose product is $-6$ . We know such two numbers are $-3\text{ and }2$ .

$15x(x^2-3x+2x-6)=0$

$15x((x^2-3x)+(2x-6))=0$

$15x(x(x-3)+2(x-3))=0$

$15x(x-3)(x+2)=0$

Now, we will use zero product property to find the zeros of our given function.

$15x=0\text{ (or) }(x-3)=0\text{ (or) }(x+2)=0$

$15x=0\text{ (or) }x-3=0\text{ (or) }x+2=0$

$\frac{15x}{15}=\frac{0}{15}\text{ (or) }x-3=0\text{ (or) }x+2=0$

$x=0\text{ (or) }x=3\text{ (or) }x=-2$

Therefore, the zeros of our given function are $x=-2,0,3$ .

7 0

3 years ago

Identify the solution(s) of the system of equations, if any. -6x - 4y = 12 12y = -18x - 36

UkoKoshka [18]

$-6x - 4y = 12|\div 2\\
12y = -18x - 36|\div 6\\\\
-3x-2y=6\\
2y=-3x-6\\\\
-3x-2y=6\\
-3x-2y=6$

Both equations are equivalent, so there are infinitely many solutions.

5 0

3 years ago

Can anybody help me with 1 and 2

Anit [1.1K]

1) $x \geq 96$
2) $x\ \textless \ 38$

Here, the variable $x$ can assume any value, and usually an inequality presented like this has $x$ as a stand-in for all real numbers. If we really wanted to make that fact clear, we could write the two inequalities like this:

$x \geq 96, x\in\mathbb{R}\\ x\ \textless \ 38, x\in\mathbb{R}$

Formally, you'd read $x\in\mathbb{R}$ as " $x$ is an element of the set of real numbers," which is a fancy way of saying that $x$ can be any real number.

8 0

3 years ago

Helping others makes a person good

oksano4ka [1.4K]

Answer:

9 cm.

Step-by-step explanation:

Let the height of the pyramid be h cm, then the height of the cuboid is (15 - h) cm.

Volume of the pyramid:

= 1/3 * h * s^2 where s is the length of a side of the square base.

= hs^2/3 cm^3

Volume of the cuboid:

= s^2(15 - h).

So we have:

hs^2/ 3 = 300.......................(1)

s^2(15 - h) = 600..................(2)

From equation (1) :

h s^2 = 900

s^2 = 900/h

Now substitute for s^2 in equation (2) :

(900/h)(15 - h) = 600

Multiply through by h:

900(15 - h) = 600h

13500 - 900h = 600h

1500h = 13500

h = 9 cm (answer). brainliest?

3 0

2 years ago