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4 years ago

13

Let a , a , be an arbitrary infinite sequence of events, and let b , b , be 12 12 another infinite sequence of events defined as

follows:

1 answer:

Alecsey [184]4 years ago

8 0

So write this and solve your problem.
Pr(Uⁿsubscript i=1 A subscript i) = ∑ⁿ subscript i=1 Pr(Bi) for n=1, 2, 3,.......

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Simplify the following expression -5[(x^3+1)(x+4)]

katrin [286]

Answer:

B

Step-by-step explanation:

-5[ (x³+1)(x+4) ] = -5[ x³*(x+4) + 1*(x+4) ]

= -5 [ x³*x + x³*4 + 1*x + 1*4 ]

= -5 [ x⁴ + 4x³ + x + 4]

= -5*x⁴ + (-5)*4x³ + (-5)*x + (-5) * 4

= -5x⁴ - 20x³ - 5x - 20

4 0

3 years ago

Find the area of a rectangle with length (2x + 3) and width (x - 4). A) 2x2 - 11x - 12 B) 2x2 - 5x + 12 C) 2x2 + 11x + 12 D) 2x2

Zielflug [23.3K]

D

area of a rectangle = length × width

area = (2x + 3)(x - 4) ( expand using FOIL )

= 2x² - 8x + 3x - 12 = 2x² - 5x - 12 → D

6 0

3 years ago

Can someone tell me how to solve translations please?

Sophie [7]

Step-by-step explanation:

Hey there!

Here; The coordinates are ; H(-4,-2), G(-5,3), F(-2,1)

The translation P(x,y) = P'(X+7,y)

Use same formula.

H(-4,-2) -------> P'(3,-2)

G(-5,3)-----------> G'(2,3)

F(-2,1)------------> F'(5,1)

<u>There</u><u>fore</u><u>,</u><u> </u><u>the</u><u> </u><u>answer</u><u> </u><u>is</u><u> </u><u>Option</u><u> </u><u>C</u><u>.</u>

<u>Hop</u><u>e</u><u> it</u><u> helps</u><u>.</u><u>.</u>

6 0

3 years ago

ANSWER ASAP! WILL

STALIN [3.7K]

Answer:

i depends on what the equation is.

7 0

3 years ago

How does the graph of g(x) = (x + 4)3 − 5 compare to the parent function f(x) = x3

vodka [1.7K]

Transforming the function using f(x - h) shifts its graph h units to the right. Here, we have h = -4, so the graph exists shifted 4 units to the left.

<h3>What are transforming functions?</h3>

The transformations of functions describe how to graph a function that exists moving and how its shape exists being changed. There exist basically three kinds of function transformations: translation, dilation, and reflection.

Let f(x) = x³ be the original function.

When -5 exists added to the y-value, it moves the point on the graph down 5 units. Compared to f(x), g(x) exists 5 units down.

f(x) = (x + 4)³ - 5

= [x- (- 4) ]³ - 5 (shift 4 units in the negative x direction that exists 4 units left)

Transforming the function using f(x - h) shifts its graph h units to the right. Here, we have h = -4, so the graph exists shifted 4 units to the left.

To learn more about transforming functions refer to:

brainly.com/question/14261221

#SPJ9

6 0

2 years ago