The y-intercept, in this case, represents when x is at 0, or when she just began observing.
Answer:
6![\frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B2%7D%7B3%7D)
Step-by-step explanation:
Deisha's build rate = 1 fence per 15 hours = 1/15 fences per hour
Travis's build rate = 1 fence per 12 hours = 1/12 fences per hour
Working together, their combined rate is 1/15 + 1/12 = 3/20 fences per hour
So it takes them 20/3 = 6 2/3 hours per fence
Answer:
Calvin: incorrect, sign error
Greg: incorrect, has no relationship to the given expression
Ruben: incorrect, sign error
Equivalent expression: 7 92(4x -11)
Step-by-step explanation:
I hope this helps you :)
<em><u>-KeairaDickson</u></em>
By definition of the derivative,
![\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{(s + h)^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7Bdr%7D%7Bds%7D%20%3D%20%5Clim_%7Bh%5Cto0%7D%20%5Cfrac%7B%5Cleft%28%5Cfrac%7B%28s%20%2B%20h%29%5E3%7D2%20%2B%201%5Cright%29%20-%20%5Cleft%28%5Cfrac%7Bs%5E3%7D2%20%2B%201%5Cright%29%7D%7Bh%7D)
![\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\left(\frac{s^3+3s^2h+3sh^2+h^3}2 + 1\right) - \left(\frac{s^3}2 + 1\right)}{h}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7Bdr%7D%7Bds%7D%20%3D%20%5Clim_%7Bh%5Cto0%7D%20%5Cfrac%7B%5Cleft%28%5Cfrac%7Bs%5E3%2B3s%5E2h%2B3sh%5E2%2Bh%5E3%7D2%20%2B%201%5Cright%29%20-%20%5Cleft%28%5Cfrac%7Bs%5E3%7D2%20%2B%201%5Cright%29%7D%7Bh%7D)
![\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac{\frac{3s^2h+3sh^2+h^3}2}{h}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7Bdr%7D%7Bds%7D%20%3D%20%5Clim_%7Bh%5Cto0%7D%20%5Cfrac%7B%5Cfrac%7B3s%5E2h%2B3sh%5E2%2Bh%5E3%7D2%7D%7Bh%7D)
![\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 \frac{3s^2h+3sh^2+h^3}{h}](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7Bdr%7D%7Bds%7D%20%3D%20%5Clim_%7Bh%5Cto0%7D%20%5Cfrac12%20%5Cfrac%7B3s%5E2h%2B3sh%5E2%2Bh%5E3%7D%7Bh%7D)
![\displaystyle\frac{dr}{ds} = \lim_{h\to0} \frac12 (3s^2+3sh+h^2)](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7Bdr%7D%7Bds%7D%20%3D%20%5Clim_%7Bh%5Cto0%7D%20%5Cfrac12%20%283s%5E2%2B3sh%2Bh%5E2%29)
![\displaystyle\frac{dr}{ds} = \frac{3s^2}2](https://tex.z-dn.net/?f=%5Cdisplaystyle%5Cfrac%7Bdr%7D%7Bds%7D%20%3D%20%5Cfrac%7B3s%5E2%7D2)
So find the area of each shape and add them.
30+30+30+30+36=156
Triangle A= 1/2xLxH
Square A= LxH