d = 3 , a₁₂ = 40 and S = 7775
In an arithmetic sequence the nth term and sum to n terms are
<h3>• a
= a₁ + (n-1)d</h3><h3>• S
=
[2a + (n-1)d]</h3><h3>
where d is the common difference</h3><h3>a₆ = a₁ + 5d = 22 ⇒ 7 + 5d = 22 ⇒ 5d = 15 ⇔ d = 3</h3><h3>a₁₂ = 7 + 11d = 7 +( 11× 3) = 7 + 33 = 40</h3><h3>S₁₀₀ =
[(2×7) +(99×3)</h3><h3> = 25(14 + 297) = 25(311)= 7775</h3>
There is no image of the table given.
Given:
approximate number = 75
exact number = 95
error = |approximate number - exact number| ÷ exact number
error = |(75-95)| / 95 = |20| / 95 = 0.21
percentage of error = 0.21 x 100% = 21%
Answer:
3.5
Step-by-step explanation:
The mean, or average, is calculated by adding up the scores and dividing the total by the number of scores
Answer:
includes: 1) a vertical shift downwards of "2" units, and 2) a horizontal shift to the left of 3 units.
Step-by-step explanation:
Let's recall the rules for transforming functions via horizontal and vertical shifts of their graphs, and pay particular attention at the operations involved in the transformation of the function leading to: .
We notice that the transformation added 3 units to the variable "x", and we also notice that there is a subtraction of 2 units to the full absolute value function. We therefore look for such changes in the list of vertical and horizontal shifts:
1) In order to shift the graph of a function vertically c units upwards, we must transform f (x) by adding c to it.
2) In order to shift the graph of a function vertically c units downwards, we must transform f (x) by subtracting c from it.
3) In order to shift the graph of a function horizontally c units to the right, we must transform the variable x by subtracting c from x.
4) In order to shift the graph of a function horizontally c units to the left, we must transform the variable x by adding c to x.
So we can conclude that the resulting function includes: 1) a vertical shift downwards of "2" units, and 2) a horizontal shift to the left of 3 units.