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uranmaximum [27]
3 years ago
5

An animal shelter has 45 cats, 10 dogs and 5 rabbits. the shelter published the ratio of cats to dogs in its latest newsletter .

what is the ratio of cats to dogs
Mathematics
1 answer:
timurjin [86]3 years ago
6 0
Ratio : cats:dogs 45:10
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Ellen is making small bags.of confetti from a large bag of confetti that weighs 4.75 pounds .If she puts the same amount of conf
BaLLatris [955]
<span>If she puts the same amount of confetti in each 5 bags  - means that she divides all amount into 5 bags.
So,
4.75 : 5 = 0.95
Answer:  each bag should weigh 0.95 pounds.</span>
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3 years ago
Find the measure of
Dmitriy789 [7]

Answer:

the 3rd One!

Step-by-step explanation:

8 0
3 years ago
Write an equation of the line that passes through (-4, -1) and is perpendicular to the line y= 4/3x+6.
scoundrel [369]

Answer:

y = (-3/4)x - 4

Step-by-step explanation:

The slopes of perpendicular lines are opposite reciprocals of each other. In other words, if the slope of one line is a/b, then the slope of the line perpendicular to it would be -b/a.

Here, the given slope is 4/3, so the slope of the perpendicular line is -3/4.

We are given a point (-4, -1) and we know the slope, so we can find the point-slope form of the line. Point-slope form is written as y - y1 = m(x - x1), where (x1,y1) is the point and m is the slope. Here, x1 = -4 and y1 = -1 and m = -3/4. So:

y - y1 = m(x - x1)

y - (-1) = (-3/4) * (x - (-4)) = (-3/4) * (x + 4)

y + 1 = (-3/4)x + (-3/4) * 4 = (-3/4)x - 3

y = (-3/4)x - 3 - 1

y = (-3/4)x - 4

3 0
3 years ago
Which equation is true?
nikitadnepr [17]

Answer:

i think its the 3rd option

5 0
3 years ago
Model Exponential Growth Question :A sample of bacteria is growing at a continuously compounding rate. The sample triples in 10
Iteru [2.4K]

Answer:

The number of bacteria B after d days is given by

B = B_0 (3)^{\frac{1}{10} d}

where B_0 is the initial number of bacteria.  

Step-by-step explanation:

The number of bacteria B in the sample triples every 10 days, this means after the first 10th day, the number of bacteria is

B = B_0 *3,

where B_0 is the initial number of bacteria in the sample.

After the 2nd 10th days, the number of bacteria is

B = (B_0 *3)*3

after the 3rd day,

B =( B_0 *3*3)*3

and so on.

Thus, the formula we get for the number of bacteria after the <em>n</em>th 10-days is

B = B_0 (3)^n

where n is is the <em>n</em>th 10-days.

Since, n is 10 days, we have

d =10n

or

n =\dfrac{1}{10}

Substituting that into B = B_0 (3)^n, we get:

\boxed{ B = B_0 (3)^{\frac{1}{10} d}}

8 0
3 years ago
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