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3 years ago

Wes melted some cheese over some tortilla chips to make nachos.

Chemistry

2 answers:

Advocard [28]3 years ago

7 0

It has a different shape

OLEGan [10]3 years ago

4 0

Answer:

Explanation:

Look through the answer choices:

A. This is definitely possible. The solid cheese was likely a solid square, but the melted cheese probably became a "blob", with no real shape - amorphous almost.

B. Unlikely; the cheese is still cheese. It didn't go through any chemical change that would affect its properties, so solid and melted cheese will taste the same.

C. Unlikely; substances only change color when they go through a chemical change. However, change of matter (melting, in this case) is a physical change, so the color should still be the same: if the solid was yellow, the melted cheese will also be yellow.

D. Wrong; when substances change state of matter, their masses don't change. Why? Mass is the measure of the amount of matter in a substance. The melted form of a substance has the same amount of matter as the solid form.

Thus, the answer is A.

Hope this helps!

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Can Magnesium hydroxide be used as the base for this titration? Why or why not? 5. Describe the procedure that you will follow t

kvasek [131]

Explanation:

Yes

2KHP + Mg(OH)2 = 2KOH + Mg(HP)2

KHP is an acidic salt which reacts with Mg(OH)2 which is a base via double displacement/decomposition reaction.

• One approach is to prepare the solution volumetrically using KHP crystals.

• Preparing 1 liter of 0.1 M KHP you would add 0.1 moles of KHP

Molar mass of KHP(C8H5KO4)

= (12*8) + (5*1) + 39 + (16*4)

= 204 g/mol

Number of moles = mass/molar mass

= 20.4/204

= 0.1 mol.

• This is added to a 1 liter volumetric flask, add deionized water until near the fill line, stopper and mix

Number of moles = molar concentration * volume

= 0.025 * 0.100

= 0.0025 mol

Equation for the reaction:

Ba(OH)2 + 2KHP --> Ba(KP)2 + 2H2O

1 mole of Ba(OH)2 reacted with 2 moles of KHP. By stoichiometry,

Number of moles of Ba(OH)2 = 0.0025/2

= 0.00125 mol.

Molarity = number of moles/volume

= 0.00125/0.01

= 0.125 M of Ba(OH)2.

4 0

3 years ago

The heat of fusion for a substance is 122 joules per gram. How many joules of heat are need to melt 7.50 grams of this substance

daser333 [38]

<h3>Answer:</h3>

915 Joules

<h3>Explanation:</h3>

The heat of fusion is the heat that is required to convert a given mass of a substance from solid state to liquid state without change in temperature.
In this case, we are given specific heat of a substance as 122 joules per gram
It means that amount of heat equivalent to 122 joules is required to change 1 gram of the substance from solid state to liquid state.

Therefore, we can determine the amount of heat needed to change 7.5 grams of the substance from solid to liquid state.

1 g = 122 Joules

7.5 g = ?

= 122 × 7.5

= 915 Joules

Thus, 7.5 g of the substance at its melting point will require 915 Joules of heat to melt.

4 0

3 years ago

Which of the following is not an example of a science? a.geology b.astrology c.astronomy d.ecology

Rasek [7]

I think it is b.astrology

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3 years ago

How could an increase in industrial activity in developing nations contribute to global climate change?

netineya [11]

If there is an increase in industrial activity, that means that more heat will be dissipated to the atmosphere in the form of carbon dioxide. Industrialization requires fuel to keep the processes on the go. At the end of the pipeline, the combustion of fuel would result to carbon dioxide released to the atmosphere. That's how it is contributing to the global climate change through the greenhouse effect.

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3 years ago

A 32.5 g iron rod, initially at 22.4 ∘C, is submerged into an unknown mass of water at 63.0 ∘C, in an insulated container. The f

a_sh-v [17]

Answer:

$m_{H_2O}=39.0g$

Explanation:

Hello,

In this case, is possible to infer that the thermal equilibrium is governed by the following relationship:

$\Delta H_{iron}=-\Delta H_{H_2O}\\m_{iron}Cp_{iron}(T_{eq}-T_{iron})=-m_{H_2O}Cp_{H_2O}(T_{eq}-T_{H_2O})$

Thus, both iron's and water's heat capacities are: 0.444 and 4.18 J/g°C respectively, so one solves for the mass of water as shown below:

$m_{H_2O}=\frac{m_{iron}Cp_{iron}(T_{eq}-T_{iron})}{-Cp_{H_2O}(T_{eq}-T_{H_2O}} \\\\m_{H_2O}=\frac{32.5g*0.444\frac{J}{g^0C}*(59.7-22.4)^0C}{-4.18\frac{J}{g^0C}*(59.7-63.0)^0C} \\\\m_{H_2O}=39.0g$

Best regards.

8 0

3 years ago