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3 years ago

Wes melted some cheese over some tortilla chips to make nachos.

Chemistry

2 answers:

Advocard [28]3 years ago

7 0

It has a different shape

OLEGan [10]3 years ago

4 0

Answer:

Explanation:

Look through the answer choices:

A. This is definitely possible. The solid cheese was likely a solid square, but the melted cheese probably became a "blob", with no real shape - amorphous almost.

B. Unlikely; the cheese is still cheese. It didn't go through any chemical change that would affect its properties, so solid and melted cheese will taste the same.

C. Unlikely; substances only change color when they go through a chemical change. However, change of matter (melting, in this case) is a physical change, so the color should still be the same: if the solid was yellow, the melted cheese will also be yellow.

D. Wrong; when substances change state of matter, their masses don't change. Why? Mass is the measure of the amount of matter in a substance. The melted form of a substance has the same amount of matter as the solid form.

Thus, the answer is A.

Hope this helps!

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From the Henderson-Hasselbalch equation, explain how the ratio [Al/[HA] changes with changing pH

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Answer:

The ratio [A-]/[HA] increase when the pH increase and the ratio decrease when the pH decrease.

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Every weak acid or base is at equilibrium with its conjugate base or acid respectively when it is dissolved in water.

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This equilibrium depends on the molecule and it acidic constant (Ka). The Henderson-Hasselbalch equation,

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3 years ago

Explain why bond angle of H2O is greater than OF2

atroni [7]

It's only a small difference (103 degrees versus 104 degrees in water), and I believe the usual rationalization is that since F is more electronegative than H, the electrons in the O-F bond spend more time away from the O (and close to the F) than the electrons in the O-H bond. That shifts the effective center of the repulsive force between the bonding pairs away from the O, and hence away from each other. So the repulsion between the bonding pairs is slightly less, while the repulsion between the lone pairs on the O is the same -- the result is the angle between the bonds is a little less.

Hope this helps!

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3 years ago