Answer:
The range of atoms = (30-300 pm) depending upon the element
Explanation:
The Atomic radii of the atom is the distance from the center of the circle to the outermost orbital.
The center of the circle is the nucleus and the radii is the outermost boundary.
The actual size of the atom is decided on the basis of the Zeff . Also known as <em>effective nuclear charge.</em>
<em>Zeff: It is the net positive charge felt by the outermost electron by the nucleus.</em>
<em>The value of Zeff depends upon the shielding constant. More the shielding less will be the Zeff . Hence the size of the atom increases.</em>
Due to shielding the outermost electrons feel less pull of nucleus.
<em>The greater the Zeff , the smaller the radius of the atom.</em>
The formula used to calculate the atomic mass is :
pm
Here "pm"= picometers
<u>The size of the smallest atom H-atom = 120 pm</u>
<u>The range of atoms = (30-300 pm)</u>
Answer:
Explanation:
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Answer:
10 kg of ice will require more energy than the released when 1 kg of water is frozen because the heat of phase transition increases as the mass increases.
Explanation:
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In this case, since the melting phase transition occurs when the solid goes to liquid and the freezing one when the liquid goes to solid, we can infer that melting is a process which requires energy to separate the molecules and freezing is a process that releases energy to gather the molecules.
Moreover, since the required energy to melt 1 g of ice is 334 J and the released energy when 1 g of water is frozen to ice is the same 334 J, if we want to melt 10 kg of ice, a higher amount of energy well be required in comparison to the released energy when 1 kg of water freezes, which is about 334000 J for the melting of those 10 kg of ice and only 334 J for the freezing of that 1 kg of water.
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First, you mix the salt and sand with water, so the salt dissolves. Next, you filter the sand out, so you have the slat water and sand separated. Then, you evaporate the water, leaving the salt behind.
The balanced chemical reaction is:
<span>2Na + 2H2O → 2NaOH + H2
</span><span>
We first use the amount of hydrogen gas to be produced and the molar mass of the hydrogen gas to determine the amount in moles to be produced. Then, we use the relation from the reaction to relate H2 to Na.
53.2 g H2 ( 1 mol / 2.02 g ) ( 2 mol Na / 1 mol H2 ) ( 22.99 g / 1 mol ) = 1210.96 g Na
1210.96 g Na ( 1 mL / 0.97 g ) = 1248.41 mL Na needed</span>
