Answer:
A POSTAL PACKAGE IS PUSHED BY A HORIZONTAL TABLE WITH A FORCE F = 40N. PACKAGE MOVES ON A DISTANCE OF 1.5M WHICH MECHANICAL WORK PERFORMS THIS FORCE
PT TEST
Great equation: distance = rate*time
So, distance run = 4.82 meters/second * 1.98 seconds = 9.5436 meters (round according to whatever the problem specifies, usually to the tenths or hundredths is sufficient).
This makes sense if you think about it since you are multiplying seconds with meters over seconds. The seconds cancel out, leaving you only the meters.
Answer:
a) V ≈ 125 m/s; b) Δt = 13.24 s; c) ΔS ≈ 1450 m
Explanation:
a) We have just to calculate the vector resultant.
V² = 106² + 66.2²
V² = 15618.44
V ≈ 125 m/s
b) The time of flight is equal to the time to reach the maximum height summed to the time to reach the land.
In vertical:
V = V₀ + a * t
V = 66.2 - g * t
0 = 66.2 - 9.8 * t
t ≈ 6.76 s
So: Δt = 13.24 s
c) In horizontal:
V = ΔS / Δt
106 = ΔS / 13.52 ⇒ ΔS = 106 * 13.52
ΔS = 106 * 13.52
ΔS = 1433,12
ΔS ≈ 1450 m
