Perimeter = 12
2(w+l) = 12
w + l = 6
area = 8
w x l = 8
the possibility
length = 4
width = 2
i know you can draw it
Answer:
m<Q = 133°
Step-by-step explanation:
From the question given above, the following data were obtained:
m<P = (x + 13)°
m<Q = (10x + 13)°
m<R = (2x – 2)°
m<Q =?
Next, we shall determine the value of x. This can be obtained as follow:
m<P + m<Q + m<R = 180 (sum of angles in a triangle)
(x + 13)° + (10x + 13)° + (2x – 2)° = 180
x + 13 + 10x + 13 + 2x – 2 = 180
x + 10x + 2x + 13 + 13 – 2 = 180
13x + 24 = 180
Collect like terms
13x = 180 – 24
13x = 156
Divide both side by 13
x = 156 / 13
x = 12
Finally, we shall determine m<Q. This can be obtained as follow:
m<Q = (10x + 13)°
x = 12
m<Q = 10(12) + 13
m<Q = 120 + 13
m<Q = 133°
1. 3x^1 + 8 - (2x^2 + 1).....distribute the negative thru the parenthesis
3x^1 + 8 - 2x^2 - 1....now combine like terms
-2x^2 + 3x^1 + 7
2. 5x^2 + 3x - 4 - (x^2 - 6x)...same thing..distribute
5x^2 + 3x - 4 - x^2 + 6x...combine like terms
4x^2 + 9x - 4
Answer:
9lb chocolate candies
6lb sugar candies
Step-by-step explanation:
Yes, I also happen to go to RSM. (6b)
Equation: 7x+2(15-x)=5*15
Solve:
7x+(2)(15)+(2)(−x)=(5)(15)
7x+30+(−2x)=75
(7x+(−2x))+(30)=75
5x+30=75
5x=45
x=9lb chocolate candies
Now, calculate the sugar candies.
15-9=6lb sugar candies
