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ziro4ka [17]
3 years ago
10

In addition to charles darwin, who also proposed a theory of evolution prompting darwin to publish his origin of species?

Biology
2 answers:
nirvana33 [79]3 years ago
4 0
Alfred Russel Wallace proposed ideas which prompted Darwin to publish his "Origin of Species". Alfred Wallace himself studied the distribution of species with respect to geographical conditions, and believed that there was some law governing the origin of new species, and it was not according to some predetermined pattern.
His paper, "On the Law which has Regulated the Introduction of New Species" was published in 1855.
dusya [7]3 years ago
3 0
Alfred Russel Wallace, a biologist, naturalist and anthropologist who studied life in the tropics of Indonesia came up with the same idea of natural selection as Charles Darwin and prompted Darwin to publish his Origin of Specie sooner rather than later. He also studied the geographic distribution of species and as as well he was a social activist who criticized capitalism and warned of damage to the environment from man's economic activities.
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Chromosome pair 23 are the sex chromosomes and are responsible for determining the gender of a human. The large chromosome is an
Mars2501 [29]

Answer:

This is true.

Explanation:

More commonly, an X chromosome will die and get replaced by a Y chromosome (all humans start off as females). When this occurs, the substitute Y chromosome causes changes in the zygote to occur; they begin developing male genitalia (i.e. penises, testicles, prostates, etc.).

5 0
3 years ago
Select ALL the correct answers.
tekilochka [14]

Answer:

(b) The interquartile range of B is greater than the interquartile range of A.

(d) The median of A is the same as the median of B.

Explanation:

Given

A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}

10th\ run = 9

So:

B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}

Required

Select all true statements

(a) & (d) Median Comparisons

A = \{1, 4, 2, 2, 3, 1, 1, 2, 1\}                         B = \{1, 4, 2, 2, 3, 1, 1, 2, 1,9\}

n = 9                                                         n = 10

Arrange the data:

A = \{1, 1, 1, 1, 2, 2,  2,3, 4\}               B = \{1,1,1,1,2,2,2,3,4,9\}

                               Median = \frac{n + 1}{2}th

Median = \frac{9 + 1}{2}th                            Median = \frac{10 + 1}{2}th

Median = \frac{10}{2}th                              Median = \frac{11}{2}th

Median = 5th                                 Median = 5.5}th --- average of 5th and 6th

Median = 2                                    Median = \frac{2+2}{2} = 2

Option (d) is correct because both have a median of: 2

(b) & (c) Interquartile Range Comparisons

A = \{1, 1, 1, 1, 2, 2,  2,3, 4\}               B = \{1,1,1,1,2,2,2,3,4,9\}

n = 9                                                         n = 10

First, calculate the lower quartile (Q1)

Q_1 = \frac{n + 1}{4}th[Odd n]             Q_1 = \frac{n}{4}th [Even n]

Q_1 = \frac{9 + 1}{4}th                            Q_1 = \frac{10}{4}th

Q_1 = \frac{10}{4}th                              Q_1 = 2.5

Q_1 = 2.5th                              

This means that:

Q_1 = 2nd + 0.5(3rd - 2nd)              Q_1 = 2nd + 0.5(3rd - 2nd)

Q_1 = 1 + 0.5(1- 1)                   Q_1 = 1+ 0.5(1 - 1)                      

Q_1 = 1                                       Q_1 = 1

Next, calculate the upper quartile (Q3)

Q_3 = \frac{3}{4}(n + 1)th [Odd n]             Q_3 = \frac{3}{4}(n)th [Even n]

Q_3 = \frac{3}{4}(9 + 1)th                            Q_3 = \frac{30}{4}th

Q_3 = \frac{30}{4}th                                     Q_3 = 7.5th  

Q_3 = 7.5th                                    

This means that:

Q_3 = 7th + 0.5(8th- 7th)           Q_3 = 7th + 0.5(8th- 7th)

Q_3 = 2 + 0.5(3- 2)                       Q_3 = 2+ 0.5(4 - 2)                      

Q_3 = 2.5                                       Q_3 = 3

The interquartile range is  IQR = Q_3 - Q_1

So, we have:

IQR = 2.5 - 1                  IQR = 3 - 1

IQR = 1.5                       IQR  =2

(b) is true because B has a greater IQR than A

(e) This is false because some spread measures (which include quartiles and the interquartile range) changed when the 10th data is included.

The upper quartile and the interquartile range of A and B are not equal

8 0
3 years ago
The shape of the beaks of Darwin's finches and industrial melanism are often cited as examples of the process of ________ leadin
SSSSS [86.1K]

Answer: The answer is natural selection

Explanation:

Natural selection explains how certain desirable traits like;

- shape of the beaks of Darwin's finches: to help them feed more easily

- industrial melanism to raise a population of dark-coloured organisms to evolve from pre-existing light coloured ones in industrial areas where the surrondings are blackened with soot;

are favored over LESS DESIRABLE TRAITS, resulting in organisms that are most suited/adapted to thrive in an environment, which is evolutionary change

6 0
3 years ago
What is the difference between algae and fungi. I need five differences. No spam..​
PSYCHO15rus [73]
Check this out. This is a table of differences between algae and fungi. Hope this helps.

4 0
3 years ago
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State the uses of excretory products in plants
d1i1m1o1n [39]

state the uses of excretory products in plants

Carbon dioxide, excess water produced during respiration and nitrogenous compounds produced during protein metabolism are the major excretory products in plants. Plants produce two gaseous waste products i.e. oxygen during photosynthesis and carbon dioxide during respiration.

Hope this helps :)

3 0
3 years ago
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