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3 years ago

Infrared radiations are produced when a changing electric field creates a

2 answers:

7 0

The last answer is correct. The infrared radiation is one of electromagnetic radiation's type, which means that changing electric field creates perpendicular changing magnetic field.

Lina20 [59]3 years ago

4 0

Answer:

Option (d)

Explanation:

When an oscillating electric and magnetic fields interacts each other perpendicularly then electromagnetic radiations are produced.

Here the changing magnetic field is created perpendicular to electric field

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Jane on her way to work walks 3 meters east, 8 meters north, and, another 3 meters east. As shown in the diagram. What is the ma

kifflom [539]

<h2><u><em> 30 meters wide and its current flows </em></u></h2><h2><u><em>Explanation:</em></u></h2><h2><u><em>Why?, Because the area of those numbers are clear to be 30. Now i'm not sure of this answer on being correct so. You should also look into other answers as well.</em></u></h2>

3 0

3 years ago

Two insulated wires, each 2.64 m long, are taped together to form a two-wire unit that is 2.64 m long. One wire carries a curren

nikklg [1K]

Answer:

$4.77\ \text{A}$

Explanation:

F = Magnetic force = 4.11 N

$I_n$ = Net current

$I_2$ = Current in one of the wires = 7.68 A

B = Magnetic field = 0.59 T

$\theta$ = Angle between current and magnetic field = $65^{\circ}$

$l$ = Length of wires = 2.64 m

$I$ = Current in the other wire

Magnetic force is given by

$F=I_nlB\sin\theta\\\Rightarrow I_n=\dfrac{F}{lB\sin\theta}\\\Rightarrow I_n=\dfrac{4.11}{2.64\times 0.59 \sin65^{\circ}}\\\Rightarrow I_n=2.91\ \text{A}$

Net current is given by

$I_n=I_2-I\\\Rightarrow I=I_2-I_n\\\Rightarrow I=7.68-2.91\\\Rightarrow I=4.77\ \text{A}$

The current I is $4.77\ \text{A}$ .

8 0

3 years ago

The Hubble Space Telescope is in a "Low-Earth Orbit" with an orbital period of 95min. Calculate the altitude of the HST's orbit

laila [671]

Answer:I don’t know please tell me

Explanation:

8 0

3 years ago

Receiver maxima problem. When the receiver moves through one cycle, how many maxima of the standing wave pattern does the receiv

shusha [124]

Answer:

Two.

Explanation:

A standing wave or stationary wave are the type of wave in which it oscillates with time but the amplitude does not move.

One complete wave consists of two loops.
It means that when the receiver moves through one cycle, two maxima of standing wave pattern the receiver pass through.

8 0

3 years ago

Suppose a 60-kg boy and a 41-kg girl use a massless rope in a tug-of-war on an icy, resistance-free surface. If the acceleration

Digiron [165]

Answer:

Approximately $2.05\; {\rm m\cdot s^{-2}}$ .

Explanation:

The net force on the girl would be:

$\begin{aligned}m(\text{girl}) \, a(\text{girl}) &= 41\; {\rm kg} \times 3.0\; {\rm m\cdot s^{-2}} \\ &= 123.0\; {\rm N} \end{aligned}$ .

Under the assumptions, the net force on this girl would be equal to the tension force in the rope. All other forces on the girl would be balanced.

In other words, the tension force that the rope exerted on the girl would be $123.0\; {\rm N}$ . The girl would exert a reaction force on the rope at the same magnitude ( $123.0\; {\rm N}\!$ ) in the opposite direction. This force would translate to a $123.0\; {\rm N}\!\!$ force on the boy towards the girl.

Under similar assumptions, the net force on the boy would also be $123.0\; {\rm N}$ . Since the mass of the boy is $m(\text{boy}) = 60\; {\rm kg}$ , the acceleration of the boy would be:

$\begin{aligned}a(\text{boy}) &= \frac{(\text{net force})}{m(\text{boy})} \\ &= \frac{123.0\; {\rm N}}{60\; {\rm kg}} \\ &= 2.05\; {\rm m\cdot s^{-2}}\end{aligned}$ .

3 0

2 years ago