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2 years ago

2. A person who weighs 800 N steps onto a scale that is

Physics

1 answer:

Fynjy0 [20]2 years ago

6 0

Answer:

дешовок в гавне овц свиней xddddd

Explanation:

дешовок в гавне овц свиней xdddddдешовок в гавне овц свиней xdddddдешовок в гавне овц свиней xdddddдешовок в гавне овц свиней xdddddдешовок в гавне овц свиней xdddddдешовок в гавне овц свиней xddddd

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A flowerpot falls from the ledge of an apartment building. A person in an apartment below, coincidentally holding a stopwatch, n

valkas [14]

Answer

given,

height of window = 4 m

time taken to travel = 1 s

acceleration due to gravity = 9.8 m/s²

$s = ut + \dfrac{1}{2}at^2$

$u = \dfrac{s - \dfrac{1}{2}at^2}{t}$

$u = \dfrac{4 - \dfrac{1}{2}\times 9.8\times 1^2}{1}$

u = -0.905 m/s

initial velocity of ledge v = 0

now,

v² = u² + 2 a s

(-0.905)² = 0 + 2 × 9.8 ×s

s = 0.042 m

6 0

3 years ago

Please I need help its timed-

leva [86]

Answer:

Explanation:

6 0

3 years ago

An object is pulled with two forces, 10 N northward and 15 N southward. The direction of the net force is to the An object is pu

ValentinkaMS [17]

Answer:

check image

Explanation:

For any question related to newons law of motion first draw the free body diagram(FBD),

7 0

4 years ago

Please help asap How can carbon monoxide be properly disposed? if you are right you will get brainliest

Elis [28]

The best way to treat CO poisoning is to breathe in pure oxygen. This treatment increases oxygen levels in the blood and helps to remove CO from the blood. Your doctor will place an oxygen mask over your nose and mouth and ask you to inhale.

Is that what you mean? Treat the poisoning? It’s a gas, so you can dispose of the gas. Unless you mean dispose of the detector?

6 0

3 years ago

A 56 kg sprinter, starting from rest, runs 49 m in 7.0 s at constant acceleration.what is the sprinter's power output at 2.0 s,

alexgriva [62]

The sprinter is in uniform accelerated motion, and its initial velocity is zero, so the relationship betwen space (S) and time (t) is
$S= \frac{1}{2} a t^2$
where a is the acceleration. Using the data of the problem, we can find a:
$a= \frac{2S}{t^2} = \frac{2 \cdot 49 m}{(7.0 s)^2} =2.0 m/s^2$
So now we can solve the 3 parts of the problem.

a) power output at t=2.0 s
The velocity at t=2.0 s is
$v(t)=at=(2.0 m/s^2)(2.0 s)=4.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(4.0 m/s)^2=448 J$

and so the power output is
$P= \frac{E}{t} = \frac{448 J}{2.0 s} =224 W$

b) power output at t=4.0s
The velocity at t=4.0 s is
$v(t)=at=(2.0 m/s^2)(4.0 s)=8.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(8.0 m/s)^2=1792 J$

and so the power output is
$P= \frac{E}{t} = \frac{1792 J}{4.0 s} =448 W$

c) Power output at t=6.0 s
The velocity at t=2.0 s is
$v(t)=at=(2.0 m/s^2)(6.0 s)=12.0 m/s$

the kinetic energy of the sprinter is
$K= \frac{1}{2} mv^2= \frac{1}{2}(56 kg)(6.0 m/s)^2=4032 J$

and so the power output is
$P= \frac{E}{t} = \frac{4032 J}{6.0 s} =672 W$

8 0

3 years ago