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AlexFokin [52]
3 years ago
7

2Al+6HBr -> 2AlBr3+3H2. When 3.22 moles of Al reacts with 4.96 moles of HBr, how many moles of H2 are formed?

Chemistry
2 answers:
Slav-nsk [51]3 years ago
7 0
2Al +6HBr ---> 3H2 + 2AlBr3 
<span>determine which is limiting... HBr is limiting </span>
<span>4.96 moles HBr ---> 1/2 (4.96) moles H2 </span>
<span>2.92 moles H2 gas</span>
Cerrena [4.2K]3 years ago
4 0
<span>2 Al+6 HBr =  2 AlBr</span>₃ <span>+ 3 H</span>₂

2 moles Al ---------  6 moles HBr ----------- 3 moles H₂
3.22 moles Al ------ 4.96 moles HBr ----- ( moles H₂ )

moles H₂ = 4.96 x 3 / 6

moles H₂ = 14.88 / 6

= 2.48 moles of H₂

hope this helps!
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