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3 years ago

PLEASE HELP NEED HELP

Chemistry

1 answer:

Harman [31]3 years ago

5 0

Explanation:

direcrly opposite is the right answer

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The standard free energy of activation of a reaction A is 81.9 kJ mol–1 (19.6 kcal mol–1) at 298 K. Reaction B is one million ti

klasskru [66]

Answer:

54.9 kJ/mol

Explanation:

The relation between the activation energy (Ea) and the rate constant (k) is given by the Arrhenius equation.

$k=A.e^{-Ea/RT}$

where,

A is a collision factor

R is the ideal gas constant

T is the absolute temperature

Reaction B is one million times faster than reaction A at the same temperature. So $k_{B}=10^{6} k_{A}$ .

Then,

$k_{B}=10^{6} k_{A}\\A.e^{-Ea_{B}/RT}=10^{6}A.e^{-Ea_{A}/RT}\\e^{-Ea_{B}/RT}=10^{6}e^{-Ea_{A}/RT}\\ln(e^{-Ea_{B}/RT})=ln(10^{6}e^{-Ea_{A}/RT})\\\frac{-Ea_{B}}{RT} =ln10^{6} -\frac{Ea_{A}}{RT} \\Ea_{B}=(ln10^{6} -\frac{Ea_{A}}{RT}).(-RT)=(ln10^{6}-\frac{89.1kJ/mol}{(8.314\times 10^{-3} kJ/mol.K).298K} ).(-8.314\times 10^{-3} \frac{kJ}{mol.K}.298K )=54.9kJ/mol$

8 0

3 years ago

What is the sum of all charges in the formula for an ionic compound?

Inessa05 [86]

Answer:

The sum of all the charges should equal the charge on the ion.

4 0

3 years ago

Why does magnesium have a larger atomic radius that chlorine

sesenic [268]

Magnesium AR: 150 pm

Chlorine AR: 100 pm

8 0

4 years ago

A block of copper has dimensions of 32cm x 21cm x 11cm. What is the mass of the block of copper ?

MatroZZZ [7]

Explanation:

The volume of the copper block is:

$32 \times 21 \times 21 = 14112 \: {cm}^{3}$

The density of copper is 8.96 g/cm³

So the mass of the copper block is

$14112 \times 8.96 = 126443.52 \: g$

or 126.44352 kg.

3 0

3 years ago

If a graduated cylinder has 28ml of water in it and you add an object which causes the water level to rise to 47ml, what is the

grin007 [14]

Answer:

The object placed in the water has a volume of 19 cm³

Explanation:

<u>Step 1: </u>Data given

volume of the cylinder before adding the object = 28 mL = 28 cm³

After adding an object with volume X the volume rises to 47 mL = 47 cm³

<u>Step 2:</u> Calculate the volume of the object

Volume of the object = Final volume - initial volume

Volume of the object = 47 cm³ (or 47 mL) - 28 cm³ ( or 28 mL) = 19 cm³ (or 19 mL)

The object placed in the water has a volume of 19 cm³

7 0

3 years ago