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aleksklad [387]
4 years ago
10

What’s the difference between the three types on natural radioactivity

Chemistry
1 answer:
Lostsunrise [7]4 years ago
3 0

Answer:

Explanation:

Alpha beta and gamma radiations are the examples of ionizing radiations. When an atom is an excited state and having high energy, the atom is in unstable state. The excess of energy is released by the atom to get the stability. The released energy is in the form of radiations which may include alpha, beta, gamma, X-ray etc.

Properties of alpha radiation:

Alpha radiations are emitted as a result of radioactive decay. The atom emit the alpha particles consist of two proton and two neutrons. Which is also called helium nuclei. When atom undergoes the alpha emission the original atom convert into the atom having mass number 4 less than and atomic number 2 less than the starting atom.

Alpha radiations can travel in a short distance.

These radiations can not penetrate into the skin or clothes.

These radiations can be harmful for the human if these are inhaled.

These radiations can be stopped by a piece of paper.

₉₂U²³⁸   →   ₉₀Th²³⁴  + ₂He⁴  + energy

Beta radiations:

Beta radiations are result from the beta decay in which electron is ejected. The neutron inside of the nucleus converted into the proton an thus emit the electron which is called β particle.

The mass of beta particle is smaller than the alpha particles.

They can travel in air in few meter distance.

These radiations can penetrate into the human skin.

The sheet of aluminium is used to block the beta radiation

⁴₆C → ¹⁴₇N + ⁰₋₁e

The beta radiations are emitted in this reaction. The one electron is ejected and neutron is converted into proton.

Gamma radiations:

Gamma radiations are high energy radiations having no mass.

These radiations are travel at the speed of light.

Gamma radiations can penetrate into the many materials.

These radiations are also used to treat the cancer.

Lead is used for the protection  against gamma radiations because of its high molecular density.

The lead apron are used by the person when treated with gamma radiations.

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What did Ernest Rutherford’s gold foil experiment demonstrate about atoms? Their positive charge is located in a small region th
sergey [27]

Their positive charge is located in a small region that is called the nucleus.

Explanation:

Ernest Rutherford in his gold foil experiment was able to demonstrate that the nucleus is made up of positive charges which occupies a small and tiny nucleus.

Rutherford bombarded a thin gold foil with alpha particles from a radioactive source.

  1. He observed that all the particles passed through but a small portion was deflected back.
  2. This led to his proposition of the nuclear model the atom.

learn more:

Ernest Rutherford brainly.com/question/1859083

#learnwithBrainly

5 0
3 years ago
Recovery standards are a necessary tool for determining exactly how much of a particular analyte you are able to extract from a
Dafna11 [192]

Answer:

2.05mg Fe/ g sample

Explanation:

In all chemical extractions you lose analyte. Recovery standards are a way to know how many analyte you lose.

In the problem you recover 3.5mg Fe / 1.0101g sample: <em>3.465mg Fe / g sample. </em>As real concentration of the standard is 4.0 mg / g of sample the percent of recovery extraction is:

3.465 / 4×100 = <em>86,6%</em>

As the recovery of your sample was 1.7mg Fe / 0.9582g, the Iron present in your sample is:

1.7mg Fe / 0.9582g sample× (100/86.6) = <em>2.05mg Fe / g sample</em>

<em></em>

I hope it helps!

5 0
4 years ago
Do you expect the O---O bond in H2O2 to be longer or shorter than the O---O bond in O2?
melomori [17]

Answer : The O-O bond in H_2O_2 will be longer than the O-O bond in O_2.

Explanation :

In the H_2O_2, the two oxygen atoms are bonded by the single bond and in O_2, the two oxygen atoms are bonded by the double bond.

As we know, the bond strength of double bond is greater than the single bond.

And the relation between the bond strength and bond length is,

\text{ Bond strength}\propto \frac{1}{\text{ Bond length}}

That means the higher the strength, the shorter will be the bond length.

Hence, the bond length of single bond will be longer than the double bond.

The structure of given molecule is shown below.

8 0
4 years ago
What can I expect on the asvab
sergiy2304 [10]
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3 0
3 years ago
Read 2 more answers
50 mL of 0.1 M acetic acid is mixed with 50 mL of 0.1 M sodium acetate (the conjugate base). The Ka of acetic acid is approximat
trapecia [35]

Answer:

4.76

Explanation:

In this case, we have to start with the <u>buffer system</u>:

CH_3COOH~->~CH_3COO^-~+~H^+

We have an acid (CH_3COOH) and a base (CH_3COO^-). Therefore we can write the <u>henderson-hasselbach reaction</u>:

pH~=~pKa+Log\frac{[CH_3COO^-]}{[CH_3COOH]}

If we want to calculate the pH, we have to <u>calculate the pKa</u>:

pH=-Log~Ka=4.76

According to the problem, we have the <u>same concentration</u> for the acid and the base 0.1M. Therefore:

[CH_3COO^-]=[CH_3COOH]

If we divide:

\frac{[CH_3COO^-]}{[CH_3COOH]}~=~1

If we do the Log of 1:

Log~1=~zero

So:

pH~=~pKa

With this in mind, the pH is 4.76.

I hope it helps!

8 0
3 years ago
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