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3 years ago

6

A balloon contains 0.5 L of air at 101.5 kPa. You squeeze it to a volume of 0.25 L. What is the pressure of air inside the ballo

on? Assume the temperature and amount of gas remain constant.
a.50.8 kPa
b.0.25 kPa
c.102 kPa
d.203 kPa

1 answer:

Igoryamba3 years ago

4 0

The answer would be D. 203kPa

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Explanation:

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morpeh [17]

<u>Answer:</u>

<u>For a:</u> The isotopic representation of iodine is $_{53}^{131}\textrm{I}$

<u>For b:</u> The isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

<u>For c:</u> The isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

<u>Explanation:</u>

The isotopic representation of an atom is: $_Z^A\textrm{X}$

where,

Z = Atomic number of the atom

A = Mass number of the atom

X = Symbol of the atom

<u>For a:</u>

We are given:

Number of neutrons = 78

Atomic number of iodine = 53 = Number of protons

Mass number = 53 + 78 = 131

Thus, the isotopic representation of iodine is $_{53}^{131}\textrm{I}$

<u>For b:</u>

We are given:

Number of neutrons = 82

Atomic number of cesium = 55 = Number of protons

Mass number = 55 + 82 = 137

Thus, the isotopic representation of cesium is $_{55}^{137}\textrm{Cs}$

<u>For c:</u>

We are given:

Number of neutrons = 52

Atomic number of strontium = 38 = Number of protons

Mass number = 38 + 52 = 90

Thus, the isotopic representation of strontium is $_{38}^{52}\textrm{Sr}$

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Explanation:

because

we know that

density of lead is 11.36 g/cm3

and

density of tin is 7.31 g/cm3

so..

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